Upload a file via <input \input> in HTML form with VBA

Question

I am trying to upload a picture file to OCR Site, however, the PDF file doesn't get uploaded into the site.

I am using the following code to achieve it and below is the HTML segment :

Sub DownPDF()

    Dim FileName As String: FileName = "C:\Users\310217955\Documents\pdfdown\SGSSI001_HL1464_2011.pdf"
    Dim DestURL As String: DestURL = "https://www.newocr.com/"
    Dim FieldName As String: FieldName = "userfile"
    Call UploadFile(DestURL, FileName, FieldName)

End Sub


'******************* upload - begin
'Upload file using input type=file
Sub UploadFile(DestURL, FileName, FieldName)
  'Boundary of fields.
  'Be sure this string is Not In the source file
  Const Boundary = "---------------------------0123456789012"

  Dim FileContents, FormData
  'Get source file As a binary data.
  FileContents = GetFile(FileName)

  'Build multipart/form-data document
  FormData = BuildFormData(FileContents, Boundary, FileName, FieldName)

  'Post the data To the destination URL
  IEPostBinaryRequest DestURL, FormData, Boundary
End Sub

'Build multipart/form-data document with file contents And header info
Function BuildFormData(FileContents, Boundary, FileName, FieldName)
  Dim FormData, Pre, Po
  Const ContentType = "application/upload"

  'The two parts around file contents In the multipart-form data.
  Pre = "--" + Boundary + vbCrLf + mpFields(FieldName, FileName, ContentType)
  Po = vbCrLf + "--" + Boundary + "--" + vbCrLf

  'Build form data using recordset binary field
  Const adLongVarBinary = 205
  Dim RS: Set RS = CreateObject("ADODB.Recordset")
  RS.Fields.Append "b", adLongVarBinary, Len(Pre) + LenB(FileContents) + Len(Po)
  RS.Open
  RS.AddNew
    Dim LenData
    'Convert Pre string value To a binary data
    LenData = Len(Pre)
    RS("b").AppendChunk (StringToMB(Pre) & ChrB(0))
    Pre = RS("b").GetChunk(LenData)
    RS("b") = ""

    'Convert Po string value To a binary data
    LenData = Len(Po)
    RS("b").AppendChunk (StringToMB(Po) & ChrB(0))
    Po = RS("b").GetChunk(LenData)
    RS("b") = ""

    'Join Pre + FileContents + Po binary data
    RS("b").AppendChunk (Pre)
    RS("b").AppendChunk (FileContents)
    RS("b").AppendChunk (Po)
  RS.Update
  FormData = RS("b")
  RS.Close
  BuildFormData = FormData
End Function

'sends multipart/form-data To the URL using IE
Function IEPostBinaryRequest(URL, FormData, Boundary)
  'Create InternetExplorer
  Dim IE: Set IE = CreateObject("InternetExplorer.Application")

  'You can uncoment Next line To see form results
  IE.Visible = True

  'Send the form data To URL As POST multipart/form-data request
  IE.Navigate URL, , , FormData, _
    "Content-Type: multipart/form-data; boundary=" + Boundary + vbCrLf

  Do While IE.Busy Or IE.readyState <> 4
    Wait 1, "Upload To " & URL
  Loop

  'Get a result of the script which has received upload
  On Error Resume Next
  IEPostBinaryRequest = IE.document.body.innerHTML
  'IE.Quit
End Function

'Infrormations In form field header.
Function mpFields(FieldName, FileName, ContentType)
  Dim MPTemplate 'template For multipart header
  MPTemplate = "Content-Disposition: form-data; name=""{field}"";" + _
   " filename=""{file}""" + vbCrLf + _
   "Content-Type: {ct}" + vbCrLf + vbCrLf
  Dim Out
  Out = Replace(MPTemplate, "{field}", FieldName)
  Out = Replace(Out, "{file}", FileName)
  mpFields = Replace(Out, "{ct}", ContentType)
End Function


Sub Wait(Seconds, Message)
  On Error Resume Next
  CreateObject("wscript.shell").Popup Message, Seconds, "", 64
End Sub


'Returns file contents As a binary data
Function GetFile(FileName)
  Dim Stream: Set Stream = CreateObject("ADODB.Stream")
  Stream.Type = 1 'Binary
  Stream.Open
  Stream.LoadFromFile FileName
  GetFile = Stream.Read
  Stream.Close
End Function

'Converts OLE string To multibyte string
Function StringToMB(S)
  Dim I, B
  For I = 1 To Len(S)
    B = B & ChrB(Asc(Mid(S, I, 1)))
  Next
  StringToMB = B
End Function
'******************* upload - end

'******************* Support
'Basic script info
Sub InfoEcho()
  Dim Msg
  Msg = Msg + "Upload file using http And multipart/form-data" & vbCrLf
  Msg = Msg + "Copyright (C) 2001 Antonin Foller, PSTRUH Software" & vbCrLf
  Msg = Msg + "use" & vbCrLf
  Msg = Msg + "[cscript|wscript] fupload.vbs file url [fieldname]" & vbCrLf
  Msg = Msg + "  file ... Local file To upload" & vbCrLf
  Msg = Msg + "  url ... URL which can accept uploaded data" & vbCrLf
  Msg = Msg + "  fieldname ... Name of the source form field." & vbCrLf
  Msg = Msg + vbCrLf + CheckRequirements
  WScript.Echo Msg
  WScript.Quit
End Sub

'Checks If all of required objects are installed
Function CheckRequirements()
  Dim Msg
  Msg = "This script requires some objects installed To run properly." & vbCrLf
  Msg = Msg & CheckOneObject("ADODB.Recordset")
  Msg = Msg & CheckOneObject("ADODB.Stream")
  Msg = Msg & CheckOneObject("InternetExplorer.Application")
  CheckRequirements = Msg
'  MsgBox Msg
End Function

'Checks If the one object is installed.
Function CheckOneObject(oClass)
  Dim Msg
  On Error Resume Next
  CreateObject oClass
  If Err = 0 Then Msg = "OK" Else Msg = "Error:" & Err.Description
  CheckOneObject = oClass & " - " & Msg & vbCrLf
End Function

Here is the HTML segment.

<input name="userfile" id="userfile" type="file">

Answer 1

I've spent several days experimenting with the same technique - using the Navigate method of the InternetExplorer.Application COM interface to upload a file.
The documentation for Navigate indicates that specifying the postdata parameter will trigger an HTTP POST, but in my experience the Content-Type is also a determining factor. Using Fiddler I found that it was consistently sending GET HTTP method instead of POST when Content-Type = multipart/form-data.

Sending the GET verb will tell the server to ignore any form data, and only process the URI.

This page indicates he had some success with the XMLHTTP object that allows finer control over the HTTP request. Here's some Powershell code that demonstrates this technique:

$http = (New-Object -ComObject "MSXML2.XMLHTTP") 
$http.Open("POST",$DestURL,$false)
$http.SetRequestHeader("Content-Type", "multipart/form-data; boundary=" + $boundary)
$http.Send($PostData) 

Answer 2

You can use ScriptUtils.ASPForm to accept uploaded files in ASP. ScriptUtils.ASPForm contains hi-performance, low resources consumption algorithm which can accept up to 2GB of data.

1. There are some steps to upload file using http and multipart/form-data document. First of all we have to read file from a disk. We can use Scripting.FileSystemObject to read text data, or ADODB.Stream to read any file. The GetFile function does the work using ADODB.Stream.

2. The second task we need to complete is a build of multipart/form-data document. The document contains from several fields separated by boundary. Each of the fields has its own header, which contains information about field name, file name and content-type of the source file. ADO Recordset object has a great method AppendChunk, which lets you join parts of multipart/form-data document (open boundary + headers + file contents + close boundary). You can see the code in BuildFormData function.

3. Last task is send the multipart/form-data document as a post request to server with multipart/form-data Content-Type header. We can use at least two object to send POST request - XMLHttp or InternetExplorer. This script uses Navigate method of InternetExplorer.Application object. You can see the code in IEPostBinaryRequest function

please look into the below link for more information.

http://www.motobit.com/tips/detpg_uploadvbsie/

GetFile method is converting the file to UTF-8. Pdf will have more than 128 byte, you need to convert it to multi byte string

'Converts OLE string To multibyte stringFunction StringToMB(S)
  Dim I, B
  For I = 1 To Len(S)
    B = B & ChrB(Asc(Mid(S, I, 1)))
  Next
  StringToMB = B End Function

Please refer this page

http://www.mrexcel.com/forum/excel-questions/861695-using-xmlhttp-upload-file-api.html#post4192153