Reputation: 23
Suppose I have a vector x which I want to convolve with itself n times. What is the good way to do this in R?
Suppose that we already have a function conv(u,v) that convolves two vectors.
I can do this:
autoconv<-function(x,n){
r<-1;
for(i in 1:n){
r<-conv(r,x);
}
return(r);
}
is there a more efficient way?
Upvotes: 2
Views: 1631
Reputation: 269684
Take the Fast Fourier Transform (fft) of x
, raise it to the kth power and take the inverse fft. Then compare that to performing convolutions of k
copies of x
. No packages are used.
# set up test data
set.seed(123)
k <- 3 # no of vectors to convolve
n <- 32 # length of x
x <- rnorm(n)
# method 1 using fft and inverse fft
yy <- Re(fft(fft(x)^k, inverse = TRUE) / n)
# method 2 using repeated convolutions
y <- x
if (k >= 2) for(i in 2:k) y <- convolve(x, y, FALSE)
# check that the two methods give the same result
all.equal(y, yy)
## TRUE
Upvotes: 4
Reputation: 6959
autoconv <- function(x, n){
if(n == 0){
return(1)
} else if(n == 1){
return(x)
} else {
i <- 2
xi <- conv(x,x)
while(n %% i != 0){
i <- i + 1
xi <- conv(xi,x)
}
return(autoconv(xi,n/i))
}
}
This will call conv()
once for each prime factor of n
, rather than n
times.
Upvotes: 1