CODEWITHSUNDEEP
c#functioncall
AllDayPiano
AllDayPiano

Reputation: 422

C# use return value from class in function call

I tried to figure it out but I don't get a clue on either how to pass a result of a new instance of a class to a function call or if this is even possible.

If I wan't to pass a random number, I'll have to create it first:

int n = 0;
Random rnd = New Random();
int m = rnd.Next(0, n);

MyClass.MyFunction(MyValue1, m);

Actually, this is 4 lines of code. However, as a newbie to c# I've already seen a lot and want to know, if there is a shorter version of this. Some pseudo code:

MyClass.MyFunction(MyValue1, Random rnd = new Random() {rnd.Next(0, n); return});

Is this somehow possible? I thought I have seen something like this but can't find anything about it.

Upvotes: 2

Views: 102

Answers (2)

Sinatr
Sinatr

Reputation: 21999

I'll simply leave this here

MyClass.MyFunction(MyValue1, ((Func<int>)(() =>
{
    int n = 0;
    var rnd = new Random();
    return rnd.Next(0, n);
}))());

P.S.: it compiles and works.

As @crashmstr commented, it's actually not a good idea specifically to Random. For single random value is ok, but for series of random numbers you don't want to create new instance every time or your numbers will become not so random.

Upvotes: 0

Kamil Budziewski
Kamil Budziewski

Reputation: 23087

You can call Next just after new Random()

MyClass.MyFunction(MyValue1, new Random().Next(0,n));

new Random() will create object of Random and on it you can call Next(). So it's possible to call it inline without need to store Random before.

Upvotes: 1

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