CODEWITHSUNDEEP
cwhile-loopdo-whilecontinue
user5405027
user5405027

Reputation:

Why aren't these continue statements working in my loops?

I'm trying to translate the following for loop into a while and a do-while loop, but for some reason the code breaks before it ever gets into the actual loop.

Here's what I'm trying to replicate:

#include <stdio.h>

int main(void)
{ int y;

  for (y=1;y<10; y++)
  { if (y == 5)
      continue;
    printf("%2d", y);
  }

  printf("\ny=%2d\n",y);

  return 0;
}

Here are my attempts at making equivalent while and do-while loops:

#include <stdio.h>

int main(void)
{
  int y;

  y = 1;
  while(y < 10)  // here's my while loop
    {
      if(y == 5)
        continue;
      printf("%2d", y);
      y++;
    }

  printf("\ny=%2d\n",y);

/********************
... and my do-while
********************/
  y = 1;
  do
    {
      if (y == 5)
        continue;
      printf("%2d", y);
      y++;
    } while(y < 10);

  printf("\ny=%2d\n",y);

  return 0;
}

Where did I go wrong?

Upvotes: 2

Views: 89

Answers (2)

Jens
Jens

Reputation: 72737

In a for loop, continue jumps to the third expression of the for statement, which increments the counter.

In a while loop, continue jumps to the next iteration immediately, skipping the increment.

Upvotes: 5

Charles
Charles

Reputation: 11489

If the condition is met in your code, you don't increment the variable and so you get stuck in an infinite loop. Try

#include <stdio.h>

int main(void)
{
  int y;

  y = 0;
  while(++y < 10)  // here's my while loop
    {
      if(y == 5)
        continue;
      printf("%2d", y);
    }

  printf("\ny=%2d\n",y);

or the like.

Upvotes: 3

Related Questions