Reputation: 79
I've been searching for an answer and it seems like I can't find it. Can anyone help me in calling void function into main 1000 times?
Here's the code:
void sahovnica()
{
int dolzina = 8;
cout<<""<< endl;
cout<<""<< endl;
char znak = 'X';
int vsakadruga = dolzina % 2;
for(int i=0; i<dolzina; i++)
{
for(int j=0; j<dolzina; j++)
{
cout << znak;
if( znak == 'X' )
znak = 'O';
else znak = 'X';
}
cout << endl;
if(!vsakadruga)
{
if( znak == 'X' )
znak = 'O';
else znak = 'X';
}
}
cout<<""<< endl;
}
______________________________________
int main(){
/*lot of functions here......
*............
*...........*/
if (nadaljevanje != 1 && nadaljevanje != 2){
cout<<"Ponovno zazenite program. Niste vnesli ne 1 ne 2."<<endl;
return 0;
}
else if (nadaljevanje ==2){
cout<<"Pridite se kdaj. Se vidimo!"<<endl;
return 0;
}
else if (nadaljevanje ==1){
sahovnica();//Need to call this "sahovnica" function 1000 times here.
}
return 0;
}
If you need any more informations, please let me know down bellow. Thanks for all the answers in advance!
Upvotes: 1
Views: 2118
Reputation:
you can put your function call inside a loop :
else if (nadaljevanje ==1){
for(int i = 0; i<1000;i++){
sahovnica();//Need to call this "sahovnica" function 1000 times here.
}
}
Upvotes: 5