CODEWITHSUNDEEP
jqueryxmlrssnodevalue
zjm1126
zjm1126

Reputation: 66787

how to get the 'guid's nodeValue in my code using google ajax feed api

this is my code :

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
  <head>
    <meta http-equiv="content-type" content="text/html; charset=utf-8"/>
    <title>Google AJAX Feed API - Simple Example</title>
    <!--<script type="text/javascript" src="http://www.google.com/jsapi"></script>-->
    <script type="text/javascript" src="http://www.google.com/jsapi"></script>
    <script type="text/javascript" src='jquery-1.4.2.js'></script>
    <script type="text/javascript">

    google.load("feeds", "1");
    function initialize() {
      var feed = new google.feeds.Feed("http://maps.google.com/maps/ms?ie=UTF8&hl=zh-CN&vps=1&jsv=259e&msa=0&output=georss&msid=109685068115364659392.00048b5b630141d82b83a");

      feed.setResultFormat(google.feeds.Feed.MIXED_FORMAT);
      feed.load(function(result) {
          if (!result.error) {
            for (var i = 0; i < result.feed.entries.length; i++) {
              var entry = result.feed.entries[i];
             var guid=entry.xmlNode.getElementsByTagName("id") || entry.xmlNode.getElementsByTagName("guid") ||0
            //console.log($('id',entry.xmlNode.xmlDocument)||$('guid',entry.xmlNode.xmlDocument))
            console.log(guid)
            }
          }
        });
  }
    google.setOnLoadCallback(initialize);

    </script>
  </head>
  <body>
    <div id="feed"></div>
  </body>

and my code did not get nothing ,

i use jquery's method text() or html() ,but not too ,

so what can i do .

thanks

Upvotes: 0

Views: 635

Answers (1)

Anurag
Anurag

Reputation: 141899

Try

$(entry.xmlNode).find('guid').text()

or 

$('guid', entry.xmlNode).text()

But, you cannot do:

$(something) || $(somethingElse)

because, the code will never get to $(somethingElse), since $(something) will return a jQuery object even if no match is found. An object (even an empty jQuery object) is truthy, thus the expression is going to be true no matter what the value of $(somethingElse), JavaScript skips evaluating it altogether. It's called short-circuit evaluation. If you do want to find first by "id", then by "guid", then try:

var xml = entry.xmlNode;
var guid = $('id', xml).text() || $('guid', xml).text() || 0;
console.log(guid);

The reason this works is because we are trying to get a string in each step of the expression, and not an object. An empty string is falsy in JavaScript, hence expressions like:

"" || 42; // 42
"" || (40 + 2); // 42

will return the second expression (42) as the result.

Upvotes: 0

Related Questions