CODEWITHSUNDEEP
c
BugHunterUK
BugHunterUK

Reputation: 8968

How do I ignore the gets() warning when compiling?

I know you quickly clicked this expecting to answer NEVER USE GETS! but I have a valid reason. I am learning about buffer overflows and need to purposely develop vulnerable software.

So, as the title states, how do I ignore the warnings so the compilation succeeds? I have tried:

gcc bo.c -o bo -Wall

... to no avail.

Thanks for any help.

Upvotes: 0

Views: 7302

Answers (2)

Vinay Singh
Vinay Singh

Reputation: 11

use fgets instead of gets

Example:

fgets (foo, sizeof(foo), stdin);

Upvotes: 1

Kenney
Kenney

Reputation: 9093

This code:

#include <stdio.h>
int main() {
        char foo[10];
        gets( foo );
        return 0;
}

produces the following output when compiled:

bo.c: In function 'main':
bo.c:4:2: warning: 'gets' is deprecated (declared at /usr/include/stdio.h:638) [-Wdeprecated-declarations]
  gets( foo );
  ^
/tmp/cclk8TkP.o: In function `main':
bo.c:(.text+0x10): warning: the `gets' function is dangerous and should not be used.

The first warning is from the compiler, and we can see what flag to use to suppress it: -Wno-deprecated-declarations.

This leaves the second warning, which is from the linker. As far as I can tell there is no way to suppress that warning easily (see here and here). However it should not be a problem, since it is a warning, not an error; the executable gets created.

Upvotes: 3

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