Reputation: 1509
I'm looking for some help with the code to sort a matrix content by the content of one column, but keeping the data of the same row... I will try to show an example:
The initial matrix is:
As you can see, the first column is the position, second is the name, third is an imaginary ID, and fourth is the age of the person.
This is a String array, so numerical data is converted using String.valueOf(number);
Now, I would like to get help with the code to sort each row, by the content of any column.
For example, rows sorted by the names column, should be something like:
Now, rows sorted by the ID column, should be something like:
As you can see, the complete row was moved, instead of just the items in a single column.
May someone help me? Thanks in advance.
Upvotes: 0
Views: 646
Reputation: 23
In c# you can make model for that specific type of array and then you can use lambda to sort it.
Exp. OrderBy(p=> p.Name)
Upvotes: 0
Reputation: 58
Here's a quick solution using Comparator and Collections. Everything it should be self explanatory. Every field is a String, but you could easily use integer as well. Hope you find it useful.
import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.List;
public class MatrixCompare {
public static void main(String[] args) {
List<Contact> contacts = new ArrayList<Contact>();
contacts.add(new Contact("1", "John", "456456", "35"));
contacts.add(new Contact("2", "Jack", "123123", "20"));
contacts.add(new Contact("3", "Mary", "234234", "24"));
contacts.add(new Contact("4", "Jane", "345345", "18"));
System.out.println("Initial List\n");
printContacts(contacts);
System.out.println("\n\nSorted by Id\n");
Collections.sort(contacts, new SortById());
printContacts(contacts);
System.out.println("\n\nSorted by Name\n");
Collections.sort(contacts, new SortByName());
printContacts(contacts);
System.out.println("\n\nSorted by Person Id\n");
Collections.sort(contacts, new SortByPersonId());
printContacts(contacts);
System.out.println("\n\nSorted by Age\n");
Collections.sort(contacts, new SortByAge());
printContacts(contacts);
}
private static void printContacts(List<Contact> contacts) {
for (int i=0; i<contacts.size(); i++) {
System.out.println(contacts.get(i).id + " - " + contacts.get(i).name + " - " +
contacts.get(i).getPersonId() + " - " + contacts.get(i).getAge());
}
}
private static class Contact {
String id;
String name;
String personId;
String age;
public Contact(String id, String name, String personId, String age) {
this.id = id;
this.name = name;
this.personId = personId;
this.age = age;
}
public String getId() {
return id;
}
public String getName() {
return name;
}
public String getPersonId() {
return personId;
}
public String getAge() {
return age;
}
}
private static class SortById implements Comparator<Contact> {
@Override
public int compare(Contact o1, Contact o2) {
String name1 = o1.getId();
String name2 = o2.getId();
return name1.compareTo(name2);
}
}
private static class SortByName implements Comparator<Contact> {
@Override
public int compare(Contact o1, Contact o2) {
String name1 = o1.getName();
String name2 = o2.getName();
return name1.compareTo(name2);
}
}
private static class SortByPersonId implements Comparator<Contact> {
@Override
public int compare(Contact o1, Contact o2) {
String name1 = o1.getPersonId();
String name2 = o2.getPersonId();
return name1.compareTo(name2);
}
}
private static class SortByAge implements Comparator<Contact> {
@Override
public int compare(Contact o1, Contact o2) {
String name1 = o1.getAge();
String name2 = o2.getAge();
return name1.compareTo(name2);
}
}
}
Upvotes: 1
Reputation: 159185
Since a 2D array is actually an array of arrays, you sort the outer array using a custom Comparator<String[]>
by calling Arrays.sort(array, comparator)
.
Upvotes: 0