CODEWITHSUNDEEP
linuxshelldate
esrtr
esrtr

Reputation: 91

Today's date and finding any day before today in shell script

echo " write a number: "
read num

Today=`date`
aday=$(date -d '-($num) day' )
echo "$Today "
echo "$aday "

I want to find any day before today. For example in my code, the user write a number such as 3. And my program will estimate this day and print it. If I write (-1) ,I can find yesterday or If I write (-3) , ı will find 3 days ago. But when I write the number which is given by user , I didn't find the day bedore today. Can you help me at this point ?

Upvotes: 0

Views: 238

Answers (1)

Damien
Damien

Reputation: 206

$num between '' won't be evaluated, you need to use "", ie:

$ foo=bar; echo " $foo"
 bar
$ foo=bar; echo ' $foo'
 $foo

So, for you example:

echo " write a number: "
read num

Today=`date`
aday=$(date -d "-$num day")
echo "$Today "
echo "$aday "

Upvotes: 1

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