CODEWITHSUNDEEP
phpjson
zgrizzly_7
zgrizzly_7

Reputation: 793

Access to the nested items from a JSON structure with foreach PHP produce error

I made this question 3 days ago, but unfurtunaly I couldn't solve my problem till now. I will formulate the question again with the hope that somebody help me.

I have the following JSON structure

{"Id":"1","Persons":[{"Name":"Luis","Time":"00:00:09","info":"","Timeext":"","Timeout":"","Timein":""}, {"Name":"Carl","Time":"00:00:03","info":"","Timeext":"","Timeout":"","Timein":""},{"Name":"Ben","Time":"00:00:08","info":"","Timeext":"","Timeout":"","Timein":""}]}

To the element Id is not a problem to access. I can get this value like this:

$arr['Id'] = $_POST['Id'];
echo $arr['Id'];

But if want to access to the structure Persons inside of the JSON, specifically to the Time value of each Person, I do like this:

 $arr['Persons'] = $_POST['Persons'];
    $jsdecode = json_decode($arr['Persons']);

    foreach ($arr['Persons'] as $p){
        echo "$p->Time <br/>";
    }

And this is the result that get:

<b>Warning</b>:  json_decode() expects parameter 1 to be string, array given in <b>C:\xampp\htdocs\Stopuhr\controller\prozess.controller.php</b> on line <b>38</b><br />
<br />
<b>Notice</b>:  Trying to get property of non-object in <b>C:\xampp\htdocs\Stopuhr\controller\prozess.controller.php</b> on line <b>41</b><br />
 <br/><br />
<b>Notice</b>:  Trying to get property of non-object in <b>C:\xampp\htdocs\Stopuhr\controller\prozess.controller.php</b> on line <b>41</b><br />
 <br/>

Can PLEASE somebody help me?

Upvotes: 3

Views: 58

Answers (2)

Kociboss
Kociboss

Reputation: 19

You have a syntax error:

{"Id":"1","Persons":[
{"Name":"Luis","Time":"00:00:09","info":"","Timeext":"","Timeout":"","Timein":""}, 
{"Name":"Carl","Time":"00:00:03","info":"","Timeext":"","Timeout":"","Timein":""},
{"Name":"Luis","Time":"00:00:08","info":"","Timeext":"","Timeout":"","Timein":""}
]}

no comma before Name Louis.

You should always validate your encoded json on http://jsonlint.com/

Upvotes: 1

kakajan
kakajan

Reputation: 2697

json_encode() - PHP Array to JSON

The json_encode() method will take a PHP array and encode it as JSON ready to be consumed by an AJAX call.

$myarray = array('Guitar' => 'Johnny', 'Vocals'=> 'Stephen', 'Bass' => 'Andy', 'Drums' => 'Mike');
$myJson = json_encode($myarray);
echo $myJson;

json_decode() - JSON to PHP Array

json_decode() will take JSON and convert it into a PHP array.

$myJson = '{"Guitar" : "Johnny", "Vocals": "Stephen", "Bass" : "Andy", "Drums" : "Mike"}';
$myarray = json_decode($myJson, true);
print_r($myarray);

Upvotes: 2

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