CODEWITHSUNDEEP
javahexdecimal
user5481831
user5481831

Reputation:

Hexadecimal to decimal in Java

Where is my mistake ?

The results are often 48 to high. For the 0 case i will add an If-statement. I want the stay with both loops if it is possible :)

public static int HexadecimalToDecimal(String hex1) {

        char hex[] = { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F' };

        int intCache = 0;
        int runner = 0;
        int help = 0;
        int number = 0;

        for (int i = hex1.length(); i > 0; i--) {


            while (hex1.charAt(i - 1) != hex[help]) {
                help++;
                number = hex[help];
            }
            intCache += number * (Math.pow(16, runner));
            runner++;
        }

        return intCache;

    }

Upvotes: 1

Views: 81

Answers (1)

Thorbjørn Ravn Andersen
Thorbjørn Ravn Andersen

Reputation: 75356

When you run

            number = hex[help];

number is assigned the character value ('0'), not the numeric value 0. The character value for '0' is 48.

Upvotes: 2

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