CODEWITHSUNDEEP
php
Fallenreaper
Fallenreaper

Reputation: 10704

date function with strtotime is going to last sunday, but i want it to be most recent sunday

I have the following line of code

$sunday = date ("m/d", strtotime("last sunday"));
$saturday = date("m/d",strtotime("this saturday"));

but if today is sunday, it will not select today. The rest of the week will be fine, because last sunday would be today. I was thinking to do like:

if (today is not sunday) {set to last sunday }else{ set to today }

similarly for saturday.

Edit:

It it acceptable to do something like, or is there a better way:

$today = date('D', strtotime("today"));
if( $today === 'Sun') {
    $sunday = date ("m/d", strtotime("today"));
}else{
    $sunday = date ("m/d", strtotime("last sunday"));
}

if ( $today === "Sat"){
    $saturday =  date ("m/d", strtotime("today"));
}else{
    $saturday = date("m/d",strtotime("this saturday"));
}

Upvotes: 0

Views: 88

Answers (2)

Michael
Michael

Reputation: 3729

I'm sure you could have come up with this yourself really, but...

What about:

function today_or_lastday ($day) {
    return date('m/d', strtotime("7 days ago")) == date('m/d', strtotime("last $day"))
        ? date('m/d', strtotime("today"))
        : date('m/d', strtotime("last $day"));
}

And:

$sunday = today_or_lastday("sunday");
$saturday = today_or_lastday("saturday");

Upvotes: 1

Hasse Björk
Hasse Björk

Reputation: 1601

I would use a line like this to get the last/current Saturday and Sunday:

$sunday   = date( 'm/d', time() - ( date( 'w' ) * 3600*24 ) );
$saturday = date( 'm/d', time() - ( ( date( 'w' ) + 1 ) % 7 * 3600*24 ) );

For Sunday we take now - days from Sunday.

date( 'w' ) gives us the weekday (0=Sunday, 1=Monday, ... 6=Saturday) and we subtract the number of days (counted in seconds 3600*24 ) that has past since Sunday.

For Saturday we do the same thing, but add a little maths trickery to adjust for it being day 6.

Upvotes: 0

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