CODEWITHSUNDEEP
javacharascii
Jayzpeer
Jayzpeer

Reputation: 81

A char between two ASCII values Java

I am a beginner at Java and I am currently writing a code where all the char symbols are printed out the same but the letters are printed out differently. How is it possible to exclude the ASCII values for the symbols? Is it possible to do something like this (where the values such as 32 and 64 represent the ASCII values corresponding to the characters) : 

char notLetter = (originalMessage.charAt(i));

     if ((32 <= notLetter <= 64) || (91 <= notLetter <= 96) || (123 <= notLetter <= 126)){
       codedMessage += notLetter;
}

Or is there a simpler way to do it ? Thanks

Edit: when i try this code, I get the following error: "<= cannot be applied to boolean, int"

Upvotes: 1

Views: 1346

Answers (4)

river226
river226

Reputation: 73

I would use the Character Object Class, with the isAlphabetic() function: http://docs.oracle.com/javase/7/docs/api/java/lang/Character.html#isAlphabetic(int)

ASCII and Unicode should match up.

Upvotes: 0

Paul Boddington
Paul Boddington

Reputation: 37655

I am not sure exactly what you are trying to do, but here is some general information.

  1. Use char literals like 'a' rather than their int values. This makes programs much easier to follow.
  2. You should use StringBuilder rather than string concatenation in most cases.
  3. Java does not support expressions like 2 <= a <= 5, so you have to do 2 <= a && a <= 5 instead.

The following code prints , !

String x = "Hello, World!";
StringBuilder sb = new StringBuilder();
for (char c : x.toCharArray()) {
    if (!(c >= 'a' && c <= 'z' || c >= 'A' && c <= 'Z')) {
        sb.append(c);
    }
}
System.out.println(sb.toString());

Upvotes: 1

Pokechu22
Pokechu22

Reputation: 5046

32 <= notLetter >= 64 is not legal in java, but 32 <= notLetter && notLetter >= 64 is allowed. However, that also will never be true — did you mean 32 <= notLetter && notLetter <= 64?

One additional thing to note that may help you: you can actually use <= with a char on both sides:

(' ' <= notLetter && <= '@')

If I am understanding what you want to do, this will do what you want:

char notLetter = (originalMessage.charAt(i));

if ((' ' <= notLetter && notLetter <= '@') || ('[' <= notLetter && notLetter <= '`') || ('{' <= notLetter && notLetter <= '~')){
    codedMessage += notLetter;
}

Upvotes: 0

LiranBo
LiranBo

Reputation: 2136

char notLetter = (originalMessage.charAt(i));

     if ((32 <= notLetter  && notLetter   <= 64) || (91 <= notLetter  && notLetter <= 96) || (123 <= notLetter && notLetter<= 126)){
       codedMessage += notLetter;
}

try this.

32 <= notLetter >= 64

This won't work for 2 reasons:

  1. The format is not supported.
  2. A number that is greater than 32 and also greater than 64 is simply any number greater than 64

Upvotes: 0

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