CODEWITHSUNDEEP
pythonrandomnested-loopsdicecumulative-sum
Lucy
Lucy

Reputation: 5

Determine average number of roll to get 1-1 on a pair of dice

Roll a pair of 6-sided dice (a.k.a. D6) until they both come up '1'. Count the number of rolls this took. Run 100 trials of this. Print out the result of each roll and report the average number of rolls required.

Use nested loops. The outer loop runs 100 trials; the inner loop continues rolling until 1-1 appears. Then update the running counts and go to the next trial.

import random
dice1, dice2 = " ", " " 
roll = " "

for roll in range(1, 101):
    roll = 0
    dice1 = random.randint(1, 6)
    dice2 = random.randint(1, 6)
    print(dice1, ",", dice2)
    while dice1 == 1 and dice2 == 1:
         break

this doesn't stop when 2 1's a rolled and i need help accumulating the roll number and trial number

Upvotes: 1

Views: 287

Answers (2)

John La Rooy
John La Rooy

Reputation: 304395

import random
from itertools import count
for roll in range(1, 101):
    for c in count(1):
        dice1 = random.randint(1, 6)
        dice2 = random.randint(1, 6)
        print(c, ':', dice1, ",", dice2)
        if dice1 == 1 and dice2 == 1:
            break

Upvotes: 0

Prune
Prune

Reputation: 77860

The problem is that your inner loop really doesn't do anything. You have to give it the work you described: keep rolling two dice until they both come up 1. I'll outline the logic you described, but have trouble implementing. I'll leave the detailed work to you. :-)

roll_count = 1
while not (dice1 == 1 and dice2 == 1):
    roll both dice
    increment roll_count

running_total += roll_count

You also need to initialize running_total somewhere.

Does this get you unstuck?

Upvotes: 1

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