Reputation: 8360
I have for example a string \try Tester234
where I want to find the Word (partially with digits)
(RegEx => (\w|\d)
) after the \try
.
But a var_dump($match)
outputs that:
array
0 =>
array
empty
1 =>
array
empty
preg_match_all('/^\\try ((\d|\w)*)/i', "\try Tester", $match);
What am I doing wrong?
Upvotes: 0
Views: 60
Reputation: 25060
You need four backslashes to insert a literal one in a regular expression:
preg_match_all('/^\\\\block ((\d|\w)*)/i', "\block Tester", $match);
which is maybe better written like this:
preg_match_all('/^\\\\block (\w+)/i', "\block Tester", $match);
Upvotes: 1