Reputation: 21
I use sqlserver 2012. I have a query like this
SELECT SUM(TH.CLEAVE_EARN_DAY), SUM(TH.CLEAVE_DAY),
SUM(TH.CLEAVE_EARN_DAY) - SUM(TH.CLEAVE_DAY)
FROM TH_LEAVE_CARD TH
The result is 0, 14.5, -15 so -15 is wrong. Must be -14.5
any suggestion ?
Upvotes: 1
Views: 181
Reputation: 624
There is few reason why the result is not as per what you are expecting. In Sql Server any math operation that contains a null would result to null. for example sum(1,2,3,null,4) is equal to null. 1 + null also equal to null.
therefore it would be safer to use isnull function to assign a default value in case the value is null.
for mathematical operation. sql server would do the calculation based on the specified data type. for example int / int = int. therefore the result would be missled. because most of the time int / int = float.
it would be better to change the value to double prior to do any arithmetic operation.
below is the example after include the isnull function as well as cast to float.
SELECT SUM(CAST(ISNULL(TH.CLEAVE_EARN_DAY,0) as double)), SUM(cast(ISNULL(TH.CLEAVE_DAY,0) as double)),
SUM(cast(ISNULL(TH.CLEAVE_EARN_DAY,0) as double)) - SUM(cast(ISNULL(TH.CLEAVE_DAY,0) as double))
FROM TH_LEAVE_CARD TH
Upvotes: 0
Reputation: 1
To perform mathematical operations on columns:
Used columns should be converted into same numeric/decimal data type.
To handle null values you may use ISNULL
function.
Ex:
SELECT SUM(TH.CLEAVE_EARN_DAY), SUM(TH.CLEAVE_DAY),
SUM(cast (TH.CLEAVE_EARN_DAY) as decimal(5,1)) - SUM(cast ( (TH.CLEAVE_DAY) as decimal(5,1))
FROM TH_LEAVE_CARD
Upvotes: 0
Reputation: 176174
Try converting all arguments to the same datatype and then do calculation:
SELECT
SUM(CAST(TH.CLEAVE_EARN_DAY AS DECIMAL(18,2))),
SUM(CAST(TH.CLEAVE_DAY AS DECIMAL(18,2))),
SUM(CAST(TH.CLEAVE_EARN_DAY AS DECIMAL(18,2))
- CAST(TH.CLEAVE_DAY AS DECIMAL(18,2))) AS substraction
FROM TH_LEAVE_CARD TH
Also you can combine:
SUM(TH.CLEAVE_EARN_DAY) - SUM(TH.CLEAVE_DAY)
to (if both column are NOT NULL
):
SUM(TH.CLEAVE_EARN_DAY - TH.CLEAVE_DAY)
or (thanks Arvo
for pointing this):
SUM(ISNULL(TH.CLEAVE_EARN_DAY,0) - ISNULL(TH.CLEAVE_DAY,0))
Upvotes: 0
Reputation: 1953
This is what you can try
SELECT SUM(TH.CLEAVE_EARN_DAY), SUM(TH.CLEAVE_DAY),
SUM(TH.CLEAVE_EARN_DAY)*1.0 - SUM(TH.CLEAVE_DAY)
FROM TH_LEAVE_CARD TH
Multiplying with 1.0 will just give you back decimal value and taking away will give you what you asked for
Upvotes: 3