CODEWITHSUNDEEP
pythonflaskgunicorn
xiº
xiº

Reputation: 4687

Gunicorn can't find app when name changed from "application"

I use gunicorn --workers 3 wsgi to run my Flask app. If I change the variable application to myapp, Gunicorn gives the error AppImportError: Failed to find application: 'wsgi'. Why am I getting this error and how do I fix it?

myproject.py:

from flask import Flask

myapp = Flask(__name__)

@myapp.route("/")
def hello():
    return 'Test!'

if __name__ == "__main__":
    myapp.run(host='0.0.0.0')

wsgi.py:

from myproject import myapp

if __name__ == "__main__":
    myapp.run()

Upvotes: 48

Views: 46225

Answers (2)

davidism
davidism

Reputation: 127320

Gunicorn (and most WSGI servers) defaults to looking for the callable named application in whatever module you point it at. Adding an alias from myproject import myapp as application or application = myapp will let Gunicorn discover the callable again.

However, the wsgi.py file or the alias aren't needed, Gunicorn can be pointed directly at the real module and callable.

gunicorn myproject:myapp --workers 16
# equivalent to "from myproject import myapp as application"

Gunicorn can also call an app factory, optionally with arguments, to get the application object. (This briefly did not work in Gunicorn 20, but was added back in 20.0.1.)

gunicorn 'myproject.app:create_app("production")' --workers 16
# equivalent to:
# from myproject.app import create_app
# application = create_app("production")

For WSGI servers that don't support calling a factory, or for other more complicated imports, a wsgi.py file is needed to do the setup.

from myproject.app import create_app
app = create_app("production")

gunicorn wsgi:app --workers 16

Upvotes: 94

duhaime
duhaime

Reputation: 27603

If you're trying to serve an app with variable name app within server/cats.py, you can start the server on port 8000 as follows:

gunicorn server.cats:app -b 0.0.0.0:8000

Upvotes: 23

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