Reputation: 223
I have a problem, which I hope can be solved..
$(".front").click(function(){
$('.front').css("display","none");
$('.back').slideDown('fast');
});
$(".back").click(function(){
$(".back").hide();
$(".front").slideDown("fast");
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="cat">
<a id="iconblock" class="front iconblock" style="background-image: url(dfgdf.png);">image</a>
<a id="iconblock" class="back iconblock" style="display: none;">text content</a></div>
<div class="cat">
<a id="iconblock" class="front iconblock" style="background-image: url(dewfgdf.png);">image2</a>
<a id="iconblock" class="back iconblock" style="display: none;">text content2</a></div>
<div class="cat">
<a id="iconblock" class="front iconblock" style="background-image: url(dfgdf.png);">image3</a>
<a id="iconblock" class="back iconblock" style="display: none;">text content3</a></div>
Eventhough I am using classes instead of ID's all blocks are flipped on click.. If use $(this).find the display of the original content does not work?
Does anyone has any solution?
Best Regards
Upvotes: 2
Views: 93
Reputation: 34199
You simply need to use this
.
$(this).hide()
will hide only the clicked item.
$(this).siblings('.back').slideDown('fast');
will find a sibling item of class .back
and slide down it, not affecting other .back
elements.
Working demo:
$(".front").click(function() {
$(this).hide();
$(this).siblings('.back').slideDown('fast');
});
$(".back").click(function() {
$(this).hide();
$(this).siblings('.front').slideDown('fast');
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="cat">
<a id="iconblock" class="front iconblock" style="background-image: url(dfgdf.png);">image</a>
<a id="iconblock" class="back iconblock" style="display: none;">text content</a></div>
<div class="cat">
<a id="iconblock" class="front iconblock" style="background-image: url(dewfgdf.png);">image2</a>
<a id="iconblock" class="back iconblock" style="display: none;">text content2</a></div>
<div class="cat">
<a id="iconblock" class="front iconblock" style="background-image: url(dfgdf.png);">image3</a>
<a id="iconblock" class="back iconblock" style="display: none;">text content3</a></div>
Upvotes: 5
Reputation: 32354
$(".front").click(function() {
$(this).hide();
$(this).next('.back').slideDown('fast');
});
$(".back").click(function() {
$(this).hide();
$(this).prev('.front').slideDown('fast');
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="cat">
<a id="iconblock" class="front iconblock" style="background-image: url(dfgdf.png);">image</a>
<a id="iconblock" class="back iconblock" style="display: none;">text content</a></div>
<div class="cat">
<a id="iconblock" class="front iconblock" style="background-image: url(dewfgdf.png);">image2</a>
<a id="iconblock" class="back iconblock" style="display: none;">text content2</a></div>
<div class="cat">
<a id="iconblock" class="front iconblock" style="background-image: url(dfgdf.png);">image3</a>
<a id="iconblock" class="back iconblock" style="display: none;">text content3</a></div>
Upvotes: 1