CODEWITHSUNDEEP
regexvim
nnyby
nnyby

Reputation: 4668

Vim regex backreference

I want to do this:

%s/shop_(*)/shop_\1 wp_\1/

Why doesn't shop_(*) match anything?

Upvotes: 68

Views: 54177

Answers (4)

Josh Bode
Josh Bode

Reputation: 3732

If you would like to avoid having to escape the capture parentheses and make the regex pattern syntax closer to other implementations (e.g. PCRE), add \v (very magic!) at the start of your pattern (see :help \magic for more info):

:%s/\vshop_(*)/shop_\1 wp_\1/

Upvotes: 3

Graham Nicholls
Graham Nicholls

Reputation: 561

@Luc if you look here: regex-info, you'll see that vim is behaving correctly. Here's a parallel from sed:

echo "123abc456" | sed 's#^([0-9]*)([abc]*)([456]*)#\3\2\1#'
sed: -e expression #1, char 35: invalid reference \3 on 's' command's RHS

whereas with the "escaped" parentheses, it works:

echo "123abc456" | sed 's#^\([0-9]*\)\([abc]*\)\([456]*\)#\3\2\1#'
456abc123

I hate to see vim maligned - especially when it's behaving correctly.

PS I tried to add this as a comment, but just couldn't get the formatting right.

Upvotes: 0

Daenyth
Daenyth

Reputation: 37431

There's several issues here.

  1. parens in vim regexen are not for capturing -- you need to use \( \) for captures.

  2. * doesn't mean what you think. It means "0 or more of the previous", so your regex means "a string that contains shop_ followed by 0+ ( and then a literal ).
    You're looking for ., which in regex means "any character". Put together with a star as .* it means "0 or more of any character". You probably want at least one character, so use .\+ (+ means "1 or more of the previous")

Use this: %s/shop_\(.\+\)/shop_\1 wp_\1/.

Optionally end it with g after the final slash to replace for all instances on one line rather than just the first.

Upvotes: 81

Stephen
Stephen

Reputation: 49156

If I understand correctly, you want %s/shop_\(.*\)/shop_\1 wp_\1/

Escape the capturing parenthesis and use .* to match any number of any character.

(Your search is searching for "shop_" followed by any number of opening parentheses followed by a closing parenthesis)

Upvotes: 33

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