Reputation: 6868
When user uploads multiple documents I am storing their files in my project like this:
Guid id;
id = Guid.NewGuid();
string filePath = Path.Combine(HttpContext.Server.MapPath("../Uploads"),
Path.GetFileName(id + item.FileName));
item.SaveAs(filePath);
So files are saved like this in my project:
Now when creating zip files I am getting same name of this files when extracting zip files but I don't want guid in my file name after user downloads file.
However I have tried to remove guid from my file name but getting error System.IO.FileNotFoundException
.
This is my code:
using (var zip = new ZipFile())
{
var str = new string[] { "1250a2d5-cd40-4bcc-a979-9d6f2cd62b9fLog.txt", "bdb31966-e3c4-4344-b02c-305c0eb0fa0aLogging.txt" }; //file name are Log.txt and Logging.txt
string[] str1 = str .Split(',');
foreach (var item in str1)
{
string filePath = Server.MapPath("~/Uploads/" + item.Substring(36));//as guid are of 36 digits
zip.AddFile(filePath, "files");
}
zip.Save(memoryStream);//Getting error here
}
Upvotes: 0
Views: 1770
Reputation: 505
You should use archive and ArchiveEntry. The rough code snipets how to do it (i don't test it):
using(var archive = new ZipArchive(memoryStream, ZipArchiveMode.Create, true)) {
{
//using(var zip = new ZipFile()) {
var str = new string[] { "1250a2d5-cd40-4bcc-a979-9d6f2cd62b9fLog.txt", "bdb31966-e3c4-4344-b02c-305c0eb0fa0aLogging.txt" }; //file name are Log.txt and Logging.txt
//string[] str = str.Split(',');
foreach(var item in str) {
using(var entryStream = archive.CreateEntry("files/" + item.Substring(36)).Open()) {
string filePath = Server.MapPath("~/Uploads/" + item);
var content = File.ReadAllBytes(filePath);
entryStream.Write(content, 0, content.Length);
}
}
}
}
sample for using DotNetZip:
using (ZipFile zip = new ZipFile())
{
var str = new string[] { "1250a2d5-cd40-4bcc-a979-9d6f2cd62b9fLog.txt", "bdb31966-e3c4-4344-b02c-305c0eb0fa0aLogging.txt" };
foreach(var item in str) {
string filePath = Server.MapPath("~/Uploads/" + item);
var content = File.ReadAllLines(filePath);
ZipEntry e = zip.AddEntry("files/" + item.Substring(36), content);
}
}
zip.Save(memoryStream);
}
Upvotes: 1
Reputation: 6868
Taking source from @kevin answer i have manage to solve this:
List<string> newfilename1 = new List<string>();
using (var zip = new ZipFile())
{
var str = new string[] { "1250a2d5-cd40-4bcc-a979-9d6f2cd62b9fLog.txt", "bdb31966-e3c4-4344-b02c-305c0eb0fa0aLogging.txt" }; //file name are Log.txt and Logging.txt
string[] str1 = str .Split(',');
foreach (var item in str1)
{
string filePath = Server.MapPath("~/Uploads/" + item);
string newFileName = Server.MapPath("~/Uploads/" + item.Substring(36));
newfilename1.Add(newFileName);
System.IO.File.Copy(filePath,newFileName);
zip.AddFile(newFileName,"");
}
zip.Save(memoryStream);
foreach (var item in newfilename1)
{
System.IO.File.Delete(item);
}
}
Upvotes: 0
Reputation: 2291
ZipFile is throwing an exception because it can't find the file on disk as you have given it a name of a file that does not exist (by doing a .Substring()). To make it work you would have to rename the file using File.Copy with your new file name and then give that same file name to Zip.AddFile().
var orgFileName = "1250a2d5-cd40-4bcc-a979-9d6f2cd62b9fLog.txt";
var newFileName = orgFileName.Substring (36);
File.Copy (orgFileName, newFileName, true);
zip.AddFile (newFileName);
Upvotes: 2