CODEWITHSUNDEEP
base64apache-camel
ferrisbueller
ferrisbueller

Reputation: 63

Unmarshaling with camel:base64 returns wrong binary

I'm using the <base64> element to unmarshal base64 code that comes as part of an XML. The route looks like this:

<route>
  <split streaming="true" strategyRef="myAggregationStaregy">
    <xpath>/*/*</xpath>
    <choice>
      <when>
        <xpath>//record</xpath>
        <to uri="file:/record.xml" />
      </when>

      <when>
        <xpath>//content</xpath>

        <unmarshal>
          <base64 />
        </unmarshal>

        <to uri="file:/content.bin" />
      </when>
    </choice>
  </split>
</route>

While the XML splitting works fine the <unmarshal> task returns rubbish. The result binary is exacly of the expected size but the bytes themselves are completely wrong.

Attempts:

Any ideas?

Upvotes: 0

Views: 850

Answers (1)

ferrisbueller
ferrisbueller

Reputation: 63

Meanwhile I found the solution: I expected the <xpath>//content</xpath> statement to filter the incoming XML so that the message body containes only the part inside the content element.

But this was wrong. This "xpath" statement is the "when" statement's predicate and it does no filtering at all.

In order to achieve the intended behaviour I had to explicitly extract my XML's "content" part and write it to the message body (using a "setBody" statement). My route finally looks like this:

<route>
  <split>
    <xpath>/*/*</xpath>
    <choice>
      <when>
        <xpath>//record</xpath>
        <to uri="file:/record.xml" />
      </when>

      <when>
        <xpath>//content</xpath>

        <setBody><xpath>//content/text()</xpath></setBody>

        <unmarshal>
          <base64 />
        </unmarshal>

        <to uri="file:/content.bin" />
      </when>
    </choice>
  </split>
</route>

Upvotes: 1

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