CODEWITHSUNDEEP
swiftnsdictionary
Hiren Panchal
Hiren Panchal

Reputation: 3023

Swift, allKeys, array, dictionary, order

I want to convert below code into swift, Actually i want do not want to loose order of keys using allKeys of nsdictionary

 NSArray *keys = [myDictionary allKeys];
keys = [keys sortedArrayUsingComparator:^(id a, id b) {
    return [a compare:b options:NSNumericSearch];
}];

Upvotes: 1

Views: 1377

Answers (2)

Deepraj Chowrasia
Deepraj Chowrasia

Reputation: 1359

For Swift 3.0 version

     let myDictionary = ["100" : "foo", "2" : "bar"]

     let keys = self.myDictionary.allKeys.sorted {
                ($0 as AnyObject).compare($1 as! String, options: .numeric) == .orderedDescending
            }
print(keys) // ["2", "100"]

.orderedDescending is used to sort the array in descending order where as .orderedAscending is used to sort the array in ascending order.

Upvotes: 0

Martin R
Martin R

Reputation: 539745

You can do the same in Swift:

let myDictionary = ["100" : "foo", "2" : "bar"]

let keys = myDictionary.keys.sort {
    $0.compare($1, options: .NumericSearch) == .OrderedAscending
}

print(keys) // ["2", "100"]

myDictionary.keys gives a (lazy collection) of all the dictionary keys and can be sorted. In contrast to sortedArrayUsingComparator (which takes a block returning -1, 0, or +1), the sort() method takes a closure returning a boolean value which is true if the lhs is "smaller" than the rhs.

Upvotes: 1

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