Reputation: 123
I am creating a grade distribution function using the following code:
def distribution(grades):
available_grades = [ 'A+','A','A-','B+','B','B-','C+','C','C-','F']
fin = open(grades,'r')
gradesList = fin.readline().split(' ')
for c_grade in available_grades:
if c_grade in gradesList:
print('students got '+c_grade)
I am using a grades.txt file which includes all of the grades and I need a way to count how many times a grade occurs in that text file and print that number like so:
distribution('grades.txt')
6 students got A
2 students got A-
3 students got B+
2 students got B
2 students got B-
4 students got C
1 student got C-
2 students got F
but currently it only prints this:
students got A
students got A-
students got B+
students got B
students got B-
students got C
students got C-
students got F
My grades.txt file consists of:
A A- C F C C B- B A A A- B B+ B+ B+ C C- B- A A A F
Upvotes: 0
Views: 1405
Reputation: 3689
Or, a pandas solution:
fin = open(grades,'r')
grades_given = fin.readline().split()
fin.close()
pd.Series(grades_given).value_counts().reset_index(name='cnt').\
apply(lambda x: "{cnt} students got {grade}".format(cnt=x['cnt'],
grade=x['index']),axis=1)
0 6 students got A
1 4 students got C
2 3 students got B+
3 2 students got A-
4 2 students got B-
5 2 students got F
6 2 students got B
7 1 students got C-
Upvotes: 1
Reputation: 11002
You can use the python Counter class for this.
from collections import counter
# creates a new Counter object
c = Counter()
# your file contents
lst_grades = "A A- C F C C B- B A A A- B B+ B+ B+ C C- B- A A A F"
# turn lst_grades to a list containing the grades
lst_grades = lst_grades.split(" ")
# printing lst_grades for a better idea what lst_grades looks like now
# lst_grades
# > ['A', 'A-', 'C', 'F', 'C', 'C', 'B-', 'B', 'A', 'A', 'A-', 'B', 'B+',
# 'B+', 'B+', 'C', 'C-', 'B-', 'A', 'A', 'A', 'F']
# call the update method of the counter c
# update takes an iterable (e.g. a list)
# and counts the values inside this iterable
c.update(lst_grades)
# now our counter contains a dictionary with the counted grads
# c
# > Counter({'A': 6, 'C': 4, 'B+': 3, 'B': 2, 'F': 2,
# 'B-': 2, 'A-': 2, 'C-': 1})
# you can simply access every counted entry
# c["A"]
# > 6
Upvotes: 1
Reputation: 24062
If you don't want to use collections, then the following should work:
def distribution(grades):
available_grades = [ 'A+','A','A-','B+','B','B-','C+','C','C-','F']
grade_dict = {}
for grade in available_grades:
grade_dict[grade] = 0
fin = open(grades,'r')
gradesList = fin.readline().split()
fin.close()
for grade in gradesList:
grade_dict[grade] += 1
for grade in available_grades:
print(str(grade_dict[grade]) + ' students got ' + grade)
Note that I removed the argument to split()
, so that it will remove all white space and not just spaces.
Upvotes: 2
Reputation: 251428
Use collections.Counter
:
def distribution(grades):
available_grades = ['A+','A','A-','B+','B','B-','C+','C','C-','F']
with open(grades, 'r') as fin:
gradeCounts = collections.Counter(fin.readline().split())
for grade in available_grades:
print(gradeCounts[grade], 'students got', grade)
Upvotes: 2