How to check if a string contains brackets ")("?

Question

I'm trying to check if an input string contains parentheses, which are: ()[]{}.

I wrote the following code:

#!/bin/bash
str="$1"
if [ -z "$str" ]; then
  echo "Usage: $(basename $0) string"
  exit 1
fi
if [[ "$str" == *['\{''}''\[''\]''('')']* ]];
then
  echo "True"
else
  echo "False"
fi

If the string contains any of these: []{} then the output is correct but if the string contains () then I get an error:

-bash: syntax error near unexpected token `('

These are the things I've tried so far:

*['\(''\)']*
*['()']*
*[()]*

Any idea how it should be written?

Edit #1:

[root@centolel ~]# date
Tue Nov  3 18:39:37 IST 2015
[root@centolel ~]# bash -x asaf.sh {
+ str='{'
+ '[' -z '{' ']'
+ [[ { == *[{}\[\]\(\)]* ]]
+ echo True
True
[root@centolel ~]# bash -x asaf.sh (
-bash: syntax error near unexpected token `('
[root@centolel ~]#

Answer 1

You can use this glob pattern with () and [] escaped inside [...]:

[[ $str == *[{}\(\)\[\]]* ]] && echo "yes" || echo "no"

Testing:

str='abc[def' && [[ $str == *[{}\(\)\[\]]* ]] && echo "yes" || echo "no"
yes

str='abc}def' && [[ $str == *[{}\(\)\[\]]* ]] && echo "yes" || echo "no"
yes

str='abc[def' && [[ $str == *[{}\(\)\[\]]* ]] && echo "yes" || echo "no"
yes

str='abc(def' && [[ $str == *[{}\(\)\[\]]* ]] && echo "yes" || echo "no"
yes

str='abc)def' && [[ $str == *[{}\(\)\[\]]* ]] && echo "yes" || echo "no"
yes

str='abc{}def' && [[ $str == *[{}\(\)\[\]]* ]] && echo "yes" || echo "no"
yes

str='abc}def' && [[ $str == *[{}\(\)\[\]]* ]] && echo "yes" || echo "no"
yes

str='abcdef' && [[ $str == *[{}\(\)\[\]]* ]] && echo "yes" || echo "no"
no