CODEWITHSUNDEEP
java
Corp. and Ltd.
Corp. and Ltd.

Reputation: 391

Java Beginner: Ignoring While loop

import java.io.*;
import java.util.*;

public class Hellno {
    public static void main(String[] args) {
        try {
            Scanner s = new Scanner(new File("words.txt"));
            findBiggest(s);
            System.out.println(findBiggest(s));
        } catch (IOException e) {
            System.out.println("Can't find that file");
        }
    }

    public static String findBiggest(Scanner scan) {
        int count0 = 0;
        int count1 = 0;
        String srs = "";

        while (scan.hasNext()) { //how do i make this the longest?
            String nsrs = scan.next();
            count0 = nsrs.length();

            if (count0 > count1) { // if the new length is bigger than what was solidified
                count1 = count0; //new solidification of number
                count0 = 0; // count becomes 0  to start again
                srs = nsrs; // nsrs has been solidified as the new biggest String
            }

            else if (count0 <= count1) { // if the new length is smaller than what was solidified
                count0 = 0; //then we start again with dummyCount = 0;
             }   
        }
        return srs;}}

I am trying to read from a text file, find out what is the longest string and return that string. However, this coding ignores all of while() and seems to jump to return srs. Why??

Upvotes: 0

Views: 201

Answers (2)

blitzqwe
blitzqwe

Reputation: 2040

need to set a delimiter on the scanner

  Scanner s = new Scanner(input).useDelimiter(System.getProperty("line.separator"));

Upvotes: 0

rgettman
rgettman

Reputation: 178253

You are calling findBiggest twice on the same Scanner. The first call presumably finds the biggest word and returns it, but it's ignored. The second call finds no words, and the while loop has no iterations.

Just call findBiggest once.

Scanner s = new Scanner(new File("words.txt"));
System.out.println(findBiggest(s));

Upvotes: 6

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