CODEWITHSUNDEEP
pythonpython-2.7
xixhxix
xixhxix

Reputation: 113

why is it giving index error out of range although i am almost sure I am in range?

i was trying to fill a list with inputs, but it gave me index out of range although the index is starting from zero, as far as i know we don't have to specify the length of a list in python.

inputs = input("Enter the number of inputs: ")
lists = []
k = 0
while k<inputs:
    lists[k]= input()
    k+=1

Upvotes: 0

Views: 59

Answers (4)

David Zemens
David Zemens

Reputation: 53653

Another possibility: Initialize lists as an empty list and then append the input with the += operand.

lists = []
k = 0
while k < inputs:
    lists += [input()]
    k+=1

Upvotes: 0

Anton Protopopov
Anton Protopopov

Reputation: 31682

You can initialize your list before using indexes of it:

lists = [0] * int(inputs)

And then you can use your code

Upvotes: 0

NPE
NPE

Reputation: 500733

Use list.append() to add an element to the end of the list:

while k<inputs:
    lists.append(input())
    k+=1

or with a list comprehension:

lists = [input() for _ in range(inputs)]

Upvotes: 0

Dimitris Fasarakis Hilliard
Dimitris Fasarakis Hilliard

Reputation: 160587

Because you are creating an empty list with lists = [] and then accessing an element of this empty list. This is the cause of the IndexError.

Appending with lists.append() helps you avoid index errors like this one. You generally want to use indexing when accessing elements and not when populating the list.

Upvotes: 1

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