Reputation: 270
There is a multi-d array and I want to reach specific field in it. I have look around it but I was unable to find proper answer to my question.
My array is like that;
array-md
columns-- 0 | 1 | 2
index 0 - [1][John][Doe]
index 1 - [2][Sue][Allen]
index 2 - [3][Luiz][Guzman]
.
.
.
index n - [n+1][George][Smith]
My question is how can I reach only second column of the array? I tried name = array[loop][1];
but it says "Cannot access a property or method of a null object reference". What is the right way to do that?
Here is main part of the code.
get
var lpx:int;
var lpxi:int;
var arrLen:int = Info.endPageArray.length;
for(lpx = 0; lpx < arrLen; lpx++)
{
for(lpxi = Info.endPageArray[lpx][2]; lpxi < Info.endPageArray[lpx][1]; lpxi++)
{
if(Info._intervalSearch[lpxi] == "completed")
{
successCount++;
Info._unitIntervalSuccess.push([lpx, successCount / (Info._intervalSearch.length / 100)]);
}
}
}
set
for(lpix = 0; lpix < arrayLength; lpix++)
{
if(lpix + 1 <= arrayLength)
{
Info.endPageArray.push([lpix, Info._UnitsTriggers[lpix + 1], Info._UnitsTriggers[lpix]]);
}
else
{
Info.endPageArray.push([lpix, Info._UnitsTriggers[lpix], Info._UnitsTriggers[lpix - 1]]);
}
}
Upvotes: 0
Views: 197
Reputation: 1997
Try this:
var tempArr:Array = [];
function pushItem(itemName:String, itemSurname:String):void
{
var tempIndex:int = tempArr.length;
tempArr[tempIndex] = {};
tempArr[tempIndex][tempIndex + 1] = {};
tempArr[tempIndex][tempIndex + 1][name] = {};
tempArr[tempIndex][tempIndex + 1][name][itemSurname] = {};
}
function getNameObject(index:int):Object
{
var result:Object;
if(index < tempArr.length)
{
result = tempArr[index][index + 1];
}
return result;
}
pushItem("Max", "Payne");
pushItem("Lara", "Croft");
pushItem("Dart", "Vader");
//
trace(getNameObject(0));
trace(getNameObject(1));
trace(getNameObject(2));
Upvotes: 2
Reputation: 9839
Multidimensional array is an array of arrays, which you can create like this :
var persons:Array = [
['John', 'Doe'],
['Sue', 'Allen'],
['Luiz','Guzman']
];
var list:Array = [];
for(var i:int = 0; i < persons.length; i++)
{
list.push([i + 1, persons[i][0], persons[i][1]]);
}
trace(list);
// gives :
//
// 1, John, Doe
// 2, Sue, Allen
// 3, Luiz, Guzman
Then to get some data :
for(var j:int = 0; j < list.length; j++)
{
trace(list[j][1]); // gives for the 2nd line : Sue
}
For more about multidimensional arrays take a look here.
Hope that can help.
Upvotes: 1