CODEWITHSUNDEEP
c#
user5515700
user5515700

Reputation:

Ignoring case sensitivity

I have to count how many times each word from given input text appears in it. And the thing where I'm stuck: The character casing differences should be ignored.

For example: "You are here.You you" -> the output :

are=1
here=1
You=3

What I've done:

string text = "You are here.You you";
IDictionary<string, int> wordsCount = new SortedDictionary<string, int>();
string[] words = text.Split(' ',',','.','-','!');

foreach (string word in words)
{
    int count = 1;
    if (wordsCount.ContainsKey(word))
        count = wordsCount[word] + 1;
    wordsCount[word] = count;
}
var items = from pair in wordsCount
            orderby pair.Value ascending
            select pair;
foreach (var p in items)
{
    Console.WriteLine("{0} -> {1}", p.Key, p.Value);
}

There is a chance to make this possible without checking manually every word from the given text? For example if I have a very long paragraph to not check every word using the specific method?

Upvotes: 1

Views: 70

Answers (2)

Rapha&#235;l Vig&#233;e
Rapha&#235;l Vig&#233;e

Reputation: 2045

Just add

for(i = 0; text[i] != '\0'; i++){
    text[i] = text[i].ToLower();
}

But as text is a string, just do :

text = text.ToLower();

Just before the string[] words = text.Split(' ',',','.','-','!'); line. And then enjoy !

Upvotes: 1

KiwiPiet
KiwiPiet

Reputation: 1334

How about linq? 

var text = "You are here.You you";
var words = text.Split(' ', ',', '.', '-', '!');

words
    .GroupBy(word => word.ToLowerInvariant())
    .OrderByDescending(group => group.Count())
    .ToList()
    .ForEach(g=> Console.WriteLine(g.Key + "=" + g.Count()));

Upvotes: 0

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