CODEWITHSUNDEEP
javascript
Becky
Becky

Reputation: 2289

Calling parameters from a function

I'm trying to learn javascript and this lesson is having me create a rock, paper, scissors game. It is asking for me to:

Call your function and pass in userChoice and computerChoice as your two arguments.

I am not sure how to pass in userChoice and computer Choice. I tried doing this:

console.log(compare + userChoice + computerChoice)

But obviously it isn't correct.

What am I doing wrong??

var userChoice = prompt("Do you choose rock, paper or scissors?");
var computerChoice = Math.random();
if (computerChoice < 0.34) {
    computerChoice = "rock";
} else if(computerChoice <= 0.67) {
    computerChoice = "paper";
} else {
    computerChoice = "scissors";
} console.log("Computer: " + computerChoice);
var compare = function(choice1, choice2) {
 if (choice1 === choice2) {
     return "The result is a tie!";
 } else if (choice1 === "rock") {
     if (choice2 === "scissors") {
         return "rock wins";
     } else {
         "paper wins";
     }
 } else if (choice1 === "paper") {
     if (choice2 === "rock") {
         return "paper wins";
     } else {
         return "scissors wins";
     }
 } else if (choice1 === "scissors") {
     if (choice2 === "rock") {
         return "rock wins";
     } else {
         return "scissors wins";
     }
 }
}
console.log(compare + userChoice + computerChoice)

Upvotes: 1

Views: 200

Answers (1)

OliverRadini
OliverRadini

Reputation: 6467

You're VERY close, arguments are passed to functions like this:

compare(userchoice, computerChoice);

Upvotes: 1

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