CODEWITHSUNDEEP
bashsed
mjswartz
mjswartz

Reputation: 743

Use sed to delete from "//" to the end of the line

So I feel like the title is self explanatory. I'm new to sed and am having trouble with the syntax to find multi character patterns like // and delete the pattern all the way to the end of the line. For example, I would like this

// here's some stuff
here's some other stuff // here's even more stuff

to turn into this

here's some other stuff

I've tried sed -i -e '/\/\*/d' $FILENAME, but that's not working.

Upvotes: 0

Views: 4263

Answers (3)

razz
razz

Reputation: 10110

sed -i 's/\/\/[^\/\/]\+$//' $FILENAME

Edit

the above code would delete the string between the last occurrence of // until the end of the line.

To delete the string from the first occurrence of // use the following as suggested in the comments:

sed -i 's/\/\/.*$//' $FILENAME

Upvotes: 0

Lizardx
Lizardx

Reputation: 1195

sed -i -e 's|//.*||' -e '/^[[:space:]]*$/d' $FILENAME

Using the | lets you not worry about the / in your pattern. The second one just deletes any ensuing lines created that only contain zero or more spaces.

echo -e '// some first comment\nsome comment // here is the comment' | sed -e 's|//.*||' -e '/^[[:space:]]*$/d'
some comment

This isn't as neat as another answer here, but it's fairly easy to read and understand.

[updated to handle deleting blank lines]

Upvotes: 2

anubhava
anubhava

Reputation: 785276

You can use this sed command with alternate regex delimiter ~:

sed -i.bak '\~^[[:blank:]]*//~d; s~//.*~~' file
here's some other stuff

\~^[[:blank:]]*//~d is used to delete all lines where // is at the start (or after some whitespaces at start).

s~//.*~~ is used to remove text starting from // where // comes in the middle.

Upvotes: 4

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