Reputation: 95
I want to write a program which receive a string value and print the decimal number.
In addition, if the string value is not 1 or 0, I need to print a message.
I wrote this code but it is always getting inside the if command.
I Would appreciate your support!
Thank you
import java.util.Random;
public class Decimal {
public static void main(String[] args) {
String input = (args[0]);
int sum = 0;
for (int i = 0; i <= input.length(); i++) {
if (!(input.charAt(i) == '0') || (input.charAt(i) == '1')) {
System.out.println("wrong string");
break;
}
char a = input.charAt(i);
if (a == '1') {
sum |= 0x01;
}
sum <<= 1;
sum >>= 1;
System.out.println(sum);
}
}
}
Upvotes: 0
Views: 143
Reputation: 159096
The !
(not) operator of the if
statement only applies to the first part:
if ( ! (input.charAt(i) == '0')
||
(input.charAt(i) == '1')
) {
So that is the same as:
if ((input.charAt(i) != '0') || (input.charAt(i) == '1')) {
When you actually meant to do:
if (input.charAt(i) != '0' && input.charAt(i) != '1') {
It's a good thing though, because once that works, you're going to get an IndexOutOfBoundsException
when i == input.length()
. Change the loop to:
for (int i = 0; i < input.length(); i++) {
And for performance, move variable a
up and use it in that first if
statement. Rename to c
or ch
is more descriptive/common.
Doing both sum <<= 1
and sum >>= 1
leaves you where you started. Is that what you wanted? You should also do the left-shift before setting the right-most bit.
Applying all that, I believe you meant to do this:
String input = args[0];
int sum = 0;
for (int i = 0; i < input.length(); i++) {
char c = input.charAt(i);
if (c != '0' && c != '1') {
System.out.println("wrong string");
break;
}
sum <<= 1;
if (c == '1')
sum |= 1;
}
System.out.println(sum);
Upvotes: 1