CODEWITHSUNDEEP
javaregexdelimiter
food-destroyer-big-bone-monsta
food-destroyer-big-bone-monsta

Reputation: 47

split regex with optional delimiters

~separate text fields~ and ^ separate all fields

String being inputed (fields can be empty)

~01001~^~0100~^~Butter, salted~^~BUTTER,WITH SALT~^~~^~~^~Y~^~~^0^~~^6.38^4.27^8.79^3.87

My current split 

String [] splited = str.split("\\^",-1);
        for (String s : splited){
            System.out.println (s);
        }

Output 

~01001~
~0100~
~Butter, salted~
~BUTTER,WITH SALT~
~~
~~
~Y~
~~
0
~~
6.38
4.27
8.79
3.87

How do change the regex so that ~~ are not included? (empty fields are fine)

What I want the output to be 

01001
0100
Butter, salted
BUTTER,WITH SALT


Y

0

6.38
4.27
8.79
3.87

Empty lines should be ""

Upvotes: 0

Views: 1229

Answers (3)

anubhava
anubhava

Reputation: 785058

Use this regex to match the data you want:

Pattern p = Pattern.compile("~([^~]*)~|([^\\^]+)");

and get the matched data using Matcher API.

Matcher m = p.matcher(input);
while (m.find()) {
   System.out.println(m.groupCount() == 2 ? m.grop(2) : m.grop(1));
}

RegEx Demo

Upvotes: 1

ergonaut
ergonaut

Reputation: 7057

It's unclear how ~ are treated, but it seems simple enough to just put both characters as a split character:

        String b[] = str.split("[\\^~]");

Which essentially ignores all ~ and ^ characters.

Upvotes: 0

Aaron
Aaron

Reputation: 24802

Splitting won't be appropriate to get rid of those tildes. You will want either to replace ~(.*?)~ with \1 or to use basic detection (charAt) and manipulation (subString)

Upvotes: 0

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