CODEWITHSUNDEEP
rdplyrdata-manipulation
John
John

Reputation: 405

Create groups based on percent_rank in dplyr

I am trying to create some groups based on the percent rank of some values in dplyr.

The code below creates a data frame and then sapply a function to determine the groups. The downside is that I can't get sapply to work for tbl_postgres, only data frames. So I'm curious if there is another solution for this.

I had considered something with ntile, but the groups I want to create have some arbitrary cut-offs. Also, I have not had much luck getting it to work with dplyr (maybe pure sql might work). 

library(dplyr)

n <- 100

df1 <- data.frame(idx = 1:n, x = rnorm(n))

df1 <- df1 %>%
            arrange(x) %>%
            mutate(pc_x = percent_rank(x))

index <- function(x) {
    if (x < 0) {
        return(NA)
    } else if (x < 0.3) {
        return(1)
    } else if (x < 0.7) {
        return(2)
    } else if (x <= 1) {
        return(3)
    } else {
        return(NA)
    }
}

df1 <- df1 %>%
            mutate(group = sapply(pc_x, index))

Upvotes: 2

Views: 1000

Answers (2)

Steven Beaupr&#233;
Steven Beaupr&#233;

Reputation: 21641

As per suggested by @joranE and @krlmlr in response to the issue you posted on GitHub, you could build your own custom sql query using sql():

library(dplyr)
library(microbenchmark)

n <- 100
set.seed(42)
df <- data.frame(idx = 1:10e5, x = rnorm(n))
copy_to(my_db, df, "df")

mbm <- microbenchmark(
joranE = tbl(my_db, sql("
  SELECT x,
    CASE
      WHEN x > 0   AND x <= 0.3 THEN 1
      WHEN x > 0.3 AND x <= 0.6 THEN 2
      WHEN x > 0.6 AND x <= 1   THEN 3
      ELSE NULL
    END
    FROM df")),
krlmlr = tbl(my_db, sql("
  SELECT x,
    CASE
      WHEN x <= 0.3 THEN
        CASE WHEN x <= 0 THEN NULL
        ELSE 1
        END
      ELSE
        CASE WHEN x <= 0.6 THEN 2
        WHEN x <= 1 THEN 3
        ELSE NULL
      END
    END
    FROM df")),
times = 100
)

Both methods yield similar results:

#Unit: milliseconds
#   expr      min       lq     mean   median       uq       max neval cld
# joranE 3.070625 3.118589 3.548202 3.206681 3.307202 30.688142   100   a
# krlmlr 3.058583 3.109567 3.250952 3.205483 3.278453  3.933817   100   a

Upvotes: 3

r2evans
r2evans

Reputation: 160782

Perhaps cut will serve your needs:

library(dplyr)
n <- 100
set.seed(42)
df1 <- data.frame(idx = 1:n, x = rnorm(n))
df1 <- df1 %>%
    arrange(x) %>%
    mutate(pc_x = percent_rank(x))

I use -1e9 in breaks because cut is "left-open", so if I used breaks <- c(0, ...) then the first row would be NA instead of 1.

breaks <- c(-1e9, 0.3, 0.7, 1)
df1 %>%
    mutate(grp = cut(pc_x, breaks=breaks, labels=FALSE)) %>%
    group_by(grp)
## Source: local data frame [100 x 4]
## Groups: grp [3]
##      idx          x       pc_x   grp
##    (int)      (dbl)      (dbl) (int)
## 1     59 -2.9930901 0.00000000     1
## 2     18 -2.6564554 0.01010101     1
## 3     19 -2.4404669 0.02020202     1
## 4     39 -2.4142076 0.03030303     1
## 5     22 -1.7813084 0.04040404     1
## ..   ...        ...        ...   ...

Upvotes: 4

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