Reputation: 3020
I have a data.table something like this. Here is the dput
of it.
structure(list(Sepal.Length = c(5.4, 5.1, 5, 5, 4.9, 4.9, 4.7,
4.6, 4.6, 4.4, 5.4, 5.1, 5, 5, 4.9, 4.9, 4.7, 4.6, 4.6, 4.4),
Sepal.Width = c(3.9, 3.5, 3.6, 3.4, 3.1, 3, 3.2, 3.4, 3.1,
2.9, 3.9, 3.5, 3.6, 3.4, 3.1, 3, 3.2, 3.4, 3.1, 2.9), Petal.Length = c(1.7,
1.4, 1.4, 1.5, 1.5, 1.4, 1.3, 1.4, 1.5, 1.4, 1.7, 1.4, 1.4,
1.5, 1.5, 1.4, 1.3, 1.4, 1.5, 1.4), Petal.Width = c(0.4,
0.2, 0.2, 0.2, 0.1, 0.2, 0.2, 0.3, 0.2, 0.2, 0.4, 0.2, 0.2,
0.2, 0.1, 0.2, 0.2, 0.3, 0.2, 0.2), Species = structure(c(1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L), .Label = c("setosa", "versicolor", "virginica"
), class = "factor"), order = c(1L, 2L, 3L, 4L, 5L, 6L, 7L,
8L, 9L, 10L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L)), .Names = c("Sepal.Length",
"Sepal.Width", "Petal.Length", "Petal.Width", "Species", "order"
), row.names = c(NA, -20L), class = c("data.table", "data.frame"
), .internal.selfref = <pointer: 0x0000000000340788>)
It looks like this. It is just a sample.
Sepal.Length Sepal.Width Petal.Length Petal.Width Species order
1: 5.4 3.9 1.7 0.4 setosa 1
2: 5.1 3.5 1.4 0.2 setosa 2
3: 5.0 3.6 1.4 0.2 setosa 3
4: 5.0 3.4 1.5 0.2 setosa 4
5: 4.9 3.1 1.5 0.1 setosa 5
6: 4.9 3.0 1.4 0.2 setosa 6
7: 4.7 3.2 1.3 0.2 setosa 7
8: 4.6 3.4 1.4 0.3 setosa 8
9: 4.6 3.1 1.5 0.2 setosa 9
10: 4.4 2.9 1.4 0.2 setosa 10
11: 5.4 3.9 1.7 0.4 setosa 1
12: 5.1 3.5 1.4 0.2 setosa 2
13: 5.0 3.6 1.4 0.2 setosa 3
14: 5.0 3.4 1.5 0.2 setosa 4
15: 4.9 3.1 1.5 0.1 setosa 5
16: 4.9 3.0 1.4 0.2 setosa 6
17: 4.7 3.2 1.3 0.2 setosa 7
18: 4.6 3.4 1.4 0.3 setosa 8
19: 4.6 3.1 1.5 0.2 setosa 9
20: 4.4 2.9 1.4 0.2 setosa 10
What I want is to swap those rows wherever column order
's value is 1 and 2 (keeping column order
as is but swap the remaining columns). So, in the above table, row 1 will get swapped with row 2 and row 11 will get swapped with row 12.
So the output will look like:
Sepal.Length Sepal.Width Petal.Length Petal.Width Species order
1: 5.1 3.5 1.4 0.2 setosa 1
2: 5.4 3.9 1.7 0.4 setosa 2
3: 5.0 3.6 1.4 0.2 setosa 3
4: 5.0 3.4 1.5 0.2 setosa 4
5: 4.9 3.1 1.5 0.1 setosa 5
6: 4.9 3.0 1.4 0.2 setosa 6
7: 4.7 3.2 1.3 0.2 setosa 7
8: 4.6 3.4 1.4 0.3 setosa 8
9: 4.6 3.1 1.5 0.2 setosa 9
10: 4.4 2.9 1.4 0.2 setosa 10
11: 5.1 3.5 1.4 0.2 setosa 1
12: 5.4 3.9 1.7 0.4 setosa 2
13: 5.0 3.6 1.4 0.2 setosa 3
14: 5.0 3.4 1.5 0.2 setosa 4
15: 4.9 3.1 1.5 0.1 setosa 5
16: 4.9 3.0 1.4 0.2 setosa 6
17: 4.7 3.2 1.3 0.2 setosa 7
18: 4.6 3.4 1.4 0.3 setosa 8
19: 4.6 3.1 1.5 0.2 setosa 9
20: 4.4 2.9 1.4 0.2 setosa 10
>
Please notice in the above output rows 1 and 2 and rows 11 and 12 of the original table have been swapped keeping column order
as is. How do I do this in the most efficient manner i.e quickly without running any loop?
Upvotes: 0
Views: 120
Reputation: 16277
Since you want to swap data, you will have to create a copy before you do the swap. In the code below, I create a df1 data.frame
, a copy of df. I use it to fetch the right rows before inserting them in the original df. I only pick the first five columns to leave df$order intact.
df <-structure(list(Sepal.Length = c(5.4, 5.1, 5, 5, 4.9, 4.9, 4.7,
4.6, 4.6, 4.4, 5.4, 5.1, 5, 5, 4.9, 4.9, 4.7, 4.6, 4.6, 4.4),
Sepal.Width = c(3.9, 3.5, 3.6, 3.4, 3.1, 3, 3.2, 3.4, 3.1,
2.9, 3.9, 3.5, 3.6, 3.4, 3.1, 3, 3.2, 3.4, 3.1, 2.9), Petal.Length = c(1.7,
1.4, 1.4, 1.5, 1.5, 1.4, 1.3, 1.4, 1.5, 1.4, 1.7, 1.4, 1.4,
1.5, 1.5, 1.4, 1.3, 1.4, 1.5, 1.4), Petal.Width = c(0.4,
0.2, 0.2, 0.2, 0.1, 0.2, 0.2, 0.3, 0.2, 0.2, 0.4, 0.2, 0.2,
0.2, 0.1, 0.2, 0.2, 0.3, 0.2, 0.2), Species = structure(c(1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L), .Label = c("setosa", "versicolor", "virginica"
), class = "factor"), order = c(1L, 2L, 3L, 4L, 5L, 6L, 7L,
8L, 9L, 10L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L)), .Names = c("Sepal.Length",
"Sepal.Width", "Petal.Length", "Petal.Width", "Species", "order"
), row.names = c(NA, -20L), class = c("data.table", "data.frame"
))
df1 <-df
df[df$order==2,1:5] <-df1[df1$order==1,1:5]
df[df$order==1,1:5] <-df1[df1$order==2,1:5]
> df
Sepal.Length Sepal.Width Petal.Length Petal.Width Species order
1 5.1 3.5 1.4 0.2 setosa 1
2 5.4 3.9 1.7 0.4 setosa 2
3 5.0 3.6 1.4 0.2 setosa 3
4 5.0 3.4 1.5 0.2 setosa 4
5 4.9 3.1 1.5 0.1 setosa 5
6 4.9 3.0 1.4 0.2 setosa 6
7 4.7 3.2 1.3 0.2 setosa 7
8 4.6 3.4 1.4 0.3 setosa 8
9 4.6 3.1 1.5 0.2 setosa 9
10 4.4 2.9 1.4 0.2 setosa 10
11 5.1 3.5 1.4 0.2 setosa 1
12 5.4 3.9 1.7 0.4 setosa 2
13 5.0 3.6 1.4 0.2 setosa 3
14 5.0 3.4 1.5 0.2 setosa 4
15 4.9 3.1 1.5 0.1 setosa 5
16 4.9 3.0 1.4 0.2 setosa 6
17 4.7 3.2 1.3 0.2 setosa 7
18 4.6 3.4 1.4 0.3 setosa 8
19 4.6 3.1 1.5 0.2 setosa 9
20 4.4 2.9 1.4 0.2 setosa 10
Upvotes: 1