Reputation: 3707
I need to implement function to
. I have the following working code:
object Main {
val m = 0
val km = 1
implicit def wrapM(v: Int) = new {
def m = v
}
implicit def wrapKm(v: Int) = new {
def km = v * 1000
}
implicit class toWrap(fromVal: Int) {
def too (value: Int): Double = {
if (value.equals(km)) {
fromVal / 1000.0
} else {
0
}
}
}
def main(args:Array[String])
{
println(53.m too km)
}
}
But there is one problem. I use too
name, instead of to
. If I rename it to to
, then I get the error:
Error:(30, 16) type mismatch;
found : Int
required: ?{def to(x$1: ? >: Int): ?}
Note that implicit conversions are not applicable because they are ambiguous:
both method intWrapper in class LowPriorityImplicits of type (x: Int)scala.runtime.RichInt
and method toWrap in object Main of type (fromVal: Int)Main.toWrap
are possible conversion functions from Int to ?{def to(x$1: ? >: Int): ?}
println(53.m to km)
^
It is due to the fact, that there is one other function to
- scala.runtime.RichInt#to
.
Upvotes: 3
Views: 344
Reputation: 6385
Scala does not allow define two implicits with same arguments set in one context....
But there is a way. You should work with different type in toWrap
implicit , instead of standard scala Int
.
Check sample below.
My idea is to implement method to
for some wrapper class IntWrap
instead of standard Int
case class IntWrap(v: Int) {
}
val m = 0
val km = 1
implicit def wrapM(v: Int) = new {
def m = IntWrap(v)
}
implicit def wrapKm(v: Int) = new {
def km = v * 1000
}
implicit class toWrap(fromVal: IntWrap) {
def to(value: Int): Double = {
if (value.equals(km)) {
fromVal.v / 1000.0
} else {
0
}
}
}
def main(args:Array[String])
{
println(53.m to km)
}
Upvotes: 3