CODEWITHSUNDEEP
pythonfile
Skyler Spaeth
Skyler Spaeth

Reputation: 193

Print file passed in as argument

I have a very simple python script that should print the contents of a file that is passed like this: python script.py stuff.txt. I don't get any output.

Here is the code:

import sys
fname = sys.argv[1]
f = open(fname, 'r')
f.read()

From what I have read, this is supposed to work. Why not?

Upvotes: 0

Views: 206

Answers (1)

spectras
spectras

Reputation: 13542

You read the file, but you don't do anything with the data.

print(f.read())

Or, for better style:

import sys
fname = sys.argv[1]
with open(fname, 'r') as f:
    print(f.read())

This is the recommended way to use files. It guarantees the file is closed when you exit the with block. Does not really matter for your small script, but it's a good habit to take.

Upvotes: 6

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