Reputation: 6231
Is there a way to create a Generic Method that uses the new()
constraint to require classes with constructor attributes of specific types?
For Example:
I have the following code:
public T MyGenericMethod<T>(MyClass c) where T : class
{
if (typeof(T).GetConstructor(new Type[] { typeof(MyClass) }) == null)
{
throw new ArgumentException("Invalid class supplied");
}
// ...
}
Is it possible to have something like this instead?
public T MyGenericMethod<T>(MyClass c) where T : new(MyClass)
{
// ...
}
EDIT: There's a suggestion regarding this. Please vote so we can have this feature in C#!
EDIT 2: The site has been taken down. Now the suggestion is on Github. Follow up there!
Upvotes: 26
Views: 9069
Reputation: 46098
Not really; C# only supports no-args constructor constraints.
The workaround I use for generic arg constructors is to specify the constructor as a delegate:
public T MyGenericMethod<T>(MyClass c, Func<MyClass, T> ctor) {
// ...
T newTObj = ctor(c);
// ...
}
then when calling:
MyClass c = new MyClass();
MyGenericMethod<OtherClass>(c, co => new OtherClass(co));
Upvotes: 35
Reputation: 164291
No, it is not possible in C# to constrain the generic type to have a constructor of a specific signature. Only the parameterless constructor is supported by new().
Upvotes: 3
Reputation: 564413
No. Unfortunately, generic constraints only allow you to include:
where T : new()
Which specifies that there is a default, parameterless constructor. There is no way to constrain to a type with a constructor which accepts a specific parameter type.
For details, see Constraints on Type Parameters.
Upvotes: 9