CODEWITHSUNDEEP
ms-accesssyntax-erroriif
Ninjatix
Ninjatix

Reputation: 75

MS Access IIf statement with multiple conditions

I am trying to use an IIf statement in ms access 2000. I've searched around but have found nothing that accurately describes my situation. The current issue is when I try to use an IIf statement to output an answer dependent upon two parts or variables, it gives me a message stating that my syntax is incorrect. The line of code in question is as follows:

=IIf([Sold]=Yes, And IIF([Paid]=No, Then,"Not Paid"))

It gives me a message saying that my syntax is incorrect but upon removing the comma after the "Yes", it tells me that I've made too few arguments.

Upvotes: 0

Views: 12081

Answers (1)

Andre
Andre

Reputation: 27644

You may be thinking of nested IIf() statements, but you only need the standard syntax:

IIf ( expr , truepart , falsepart )

expr is [Sold]=Yes And [Paid]=No. And there is no Then in IIf.

So your code should be:

=IIf([Sold]=Yes And [Paid]=No, "Not Paid", "Paid!")

or with a more common way to formulate the bool expression, and an empty falsepart:

=IIf([Sold] And Not [Paid], "Not paid", "")

Upvotes: 1

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