CODEWITHSUNDEEP
c#.netasp.net-mvc
Pectus Excavatum
Pectus Excavatum

Reputation: 3773

How can I get the name of the view being displayed in the ASP.NET MVC

I have a form that creates a new slide (part of a simple CMS) and currently I declare the form using the following code:

Create:

@model Models.Slide
@{
    ViewBag.Title = "Create New Slide";
    Layout = "~/Areas/Admin/Views/Slide/_SlideLayout.cshtml";
}

 <h2>Create Slide</h2>

 @Html.Partial("_SlideForm", Model)

Slide Form

@model Models.Slide

@using (Html.BeginForm("Create", "Slide", null, FormMethod.Post, new { enctype = "multipart/form-data" }))
{
    @Html.AntiForgeryToken()

    <div class="form-horizontal">
    <h4>Slide</h4>
    <hr />
    ....

Edit:

@model Models.Slide
@{
    ViewBag.Title = "Edit New Slide";
    Layout = "~/Areas/Admin/Views/Slide/_SlideLayout.cshtml";
}

 <h2>Edit Slide</h2>

 @Html.Partial("_SlideForm", Model)

These form is a partial view and I call this partial view within a "Create" view that calls a create method in my controller.

However, I want to have an "Edit" view that also calls this partial view to render the slide form, but I obviously want to call a different action method (i.e. an edit method not a create method).

I know I could simply redo the whole form and change the action method in the begin form call to "Edit" but this seems like a lot of unnecessary duplication. Is there a way to get what view called this partial view. I.e. is there a way I can determine if the form should use "Create" or "Edit" in the begin form call? The views themselves are called Create and Edit.

Many thanks

Upvotes: 0

Views: 140

Answers (3)

Shyju
Shyju

Reputation: 218702

You may use the same HttpPost action method for both Create and Edit. The only difference between edit and Create is, For Edit, You will have an ID for which you want to edit the details. So why not use the value of id to determine whether the form is being posted from Create view or Edit view ?

public CreateOrEditVM
{
  public int SlideId {set;get;}
  public string SlideName {set;get;}
}

And in your controller.

public ActionResult Create()
{
  return View(new CreateOrEditVM());
}
public ActionResult Edit(int id)
{
  var vm = new CreateOrEditVM()'
  var slide = yourService.GetSlideFromId(id);
  vm.SlideId=slide.Id;
  vm.SlideName = slide.Name;
  return View(vm);
}

[HttpPost]
public ActionResult Create(CreateOrEditVM model)
{
   if(model.SlideId==0)
   {
      // coming from Create form 
   }
   else
   {
     //Coming from Edit form
   }
   // to do :Save and redirect
}

Make sure you have the SlideId value in the partial view.

@model CreateOrEditVM
@using(Html.Beginform())
{
  @Html.TextboxFor(s=>s.SlideName)
  @Html.HiddenFor(s=>s.SlideId)
  <input type="submit" />
}

If you want, You can use the same get method for create and edit, Use a nullable integer as the param and based on the value, Return the viewmodel.

Upvotes: 0

Andrii Tsok
Andrii Tsok

Reputation: 1446

Just set value to your ViewBag in each ActionMethod.

public ActionResult Edit()
{

    // Do some edit stuff
    ViewBag.FormType = "Create";
    return View();
}

public ActionResult Create()
{
    // Do some create stuff
    ViewBag.FormType = "Create";
    return View();
}

And then use it in your Razor view:

@model Models.Slide
@{
    Layout = "~/Areas/Admin/Views/Slide/_SlideLayout.cshtml";
}

 <h2>@ViewBag.FormType Slide</h2>

 @Html.Partial("_SlideForm", Model)

Upvotes: 1

Matija Gobec
Matija Gobec

Reputation: 880

Can you pass additional parameter when you create this partial ? Something like

 @using(Html.BeginForm("Partial", "Controller",
        new { action = "Edit" }, FormMethod.Post, null)

Upvotes: 0

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