Java number sum

Question

I have code who makes random numbers and prints them. And it counts numbers who are bigger than 250. How can I output in a one number? I need sum the results numbers.

Like this:

315 32 486 311 58

430 145 83 395 312

223 455 370 151 84

163 415 433 75 194

152 457 427 218 301

142 298 300 404 24

15 296 368 196 438

102 410 351 341 328

results:

3 3 2 2 3 3 3 4

        Random rnd = new Random();
        if (ch=='Y' || ch=='y') {
            for (i=0; i<8; i++)
                for (j=0; j<5; j++) 
                    A[i][j] = rnd.nextInt((500 - 10) + 1) + 10;

        }
        else
            if (ch != 'N' && ch != 'n') {
                System.out.println("input-output error");
                return;
            }

        for (i=0; i<8; i++) {
            for (j=0; j<5; j++)
                System.out.print(A[i][j] + "\t");
            System.out.println();
        }

        System.out.println("results: ");
        for (i=0; i<8; i++) {
            res = 0;
            for (j=0; j<5; j++) {
                if (A[i][j] >= 250) res++;

            }

                System.out.print((res) + " ");
        }
    }
}

Answer 1

You can count the numbers that are greater than threshold in the loop that prints them, like this:

    int res = 0;
    for (i=0; i<8; i++) {
        for (j=0; j<5; j++) {
            System.out.print(A[i][j] + "\t");
            if (A[i][j] >= 250) res++;
        }
        System.out.println();
    }

    System.out.println("results: " + res);