CODEWITHSUNDEEP
listerlang
user2092864
user2092864

Reputation:

How to make a sequence function for lists?

I'm trying to create a list in Erlang which will hold a number of integers. So if I pass in 5 it will create a list holding [1,2,3,4,5]. This is the code I have so far.

So I'd want to call the list something like tower1

-module(towers).

-export([create_towers/1]).

create_towers( 0 ) -> [];
create_towers( N ) when N > 0 -> create_towers( N-1 ) ++ [N].

Upvotes: 2

Views: 102

Answers (1)

rorra
rorra

Reputation: 9693

The code is good, the problem is the syntax

-module(towers).

-export([create_towers/1]).

create_towers(0) ->
    [];
create_towers(N) when N > 0 ->
    create_towers(N-1) ++ [N].

works fine

Eshell V7.1  (abort with ^G)
(emacs@Mac-mini-de-Rodrigo)1> c("/Users/rorra/erlang/towers", [{outdir, "/Users/rorra/erlang/"}]).
{ok,towers}
(emacs@Mac-mini-de-Rodrigo)2> towers:create_towers(0).
[]
(emacs@Mac-mini-de-Rodrigo)3> towers:create_towers(10).
[1,2,3,4,5,6,7,8,9,10]

If you want it to call the list created tower1:

 (emacs@Mac-mini-de-Rodrigo)2> Tower1 = towers:create_towers(5).
 [1,2,3,4,5]

notice that all variables starts with upperase, if you want to name the module towers1, change the file name to tower1.erl and add:

-module(tower1).

-export([create_towers/1]).

create_towers(0) ->
    [];
create_towers(N) when N > 0 ->
    create_towers(N-1) ++ [N].

and then you can call towers1:create_towers(N) like:

(emacs@Mac-mini-de-Rodrigo)2> MyVar = tower1:create_towers(5).
[1,2,3,4,5]

Upvotes: 1

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