Reputation: 9140
I have this code in Swift:
guard let user = username else{
return nil
}
But I'm getting the following errors:
Nil is incompatible with return type String
Any of you knows why or how I return nil in this case?
I'll really appreciate your help
Upvotes: 13
Views: 26966
Reputation: 366
You have to tell the compiler that you want to return nil
. How do you that? By assigning ?
after your object. For instance, take a look at this code:
func newFriend(friendDictionary: [String : String]) -> Friend? {
guard let name = friendDictionary["name"], let age = friendDictionary["age"] else {
return nil
}
let address = friendDictionary["address"]
return Friend(name: name, age: age, address: address)
}
Notice how I needed to tell the compiler that my object Friend
, which I'm returning, is an optional Friend?
. Otherwise it will throw an error.
Upvotes: 21
Reputation: 1
*Does your function declare an optional return type?
func minAndmax(array:[Int])->(min:Int, max:Int)? {
if array.isEmpty {
return nil
}
var currentMin = array[0]
var currentMax = array[0]
for value in array {
if value < currentMin {
currentMin = value
}
else if value > currentMax {
currentMax = value
}
}
return (currentMin, currentMax)
}
if let bounds = minAndmax(array: [8, -6, 2, 109, 3, 71]) {
print(bounds)
}
Upvotes: 0
Reputation: 507
Does your function declare an optional return type?
func foo() -> String? { ...
NOTE
The concept of optionals doesn’t exist in C or Objective-C. The nearest thing in Objective-C is the ability to return nil from a method that would otherwise return an object, with nil meaning “the absence of a valid object.”
Upvotes: 28