Reputation: 131
I want to set a constraint for every x value, 0<=f(x,vctr)<=100. The result is:
??? Undefined function or variable 'x' due to functional constraint "cnstrnt".
Although it is a variable, fmincon
asks for a value of x
in cnstrnt
. x
represents multiple variables. b
, k
, and vctr
(vector of constants) are constants. What is the correct way of coding the constraint?
function [ h ] = f(x,vctr)
g=@(x) (vctr(1,6).*x.^5+vctr(1,5).*x.^4+vctr(1,4).*x.^3+ ...
vctr(1,3).*x.^2+vctr(1,2).*x.^1+vctr(1,1));
h=fzero( @(x)(g(x)-y),0);
end
function [ cc,ceq ] = cnstrnt(x,b,vctr)
for k=1:length(b)*2
cc(k)=f(x(k),vctr)-100;
cc(k+1)=-f(x(k),vctr);
end
ceq=[];
end
[result,FVAL,EXITFLAG,OUTPUT,LAMBDA,GRAD,HESSIAN]= fmincon(@(x)obj(x,b,c,L,vctr) ,x0,A,B,Aeq,beq,[],ub,cnstrnt(x,b,vctr),opts);
??? Undefined function or variable 'x'.
Upvotes: 0
Views: 91
Reputation: 131
The variable must be declared with @(x)
as @(x)cnstrnt(x,b,vctr)
. Then fmincon
can recognize the variables and differentiate from the constants.
[result,FVAL,EXITFLAG,OUTPUT,LAMBDA,GRAD,HESSIAN]= fmincon(@(x)obj(x,b,c,L,vctr) ,x0,A,B,Aeq,beq,[],ub,@(x)cnstrnt(x,b,vctr),opts);
Upvotes: 1