Reputation: 391
I need a method that given input 2D array {{1,2},{3,4}} and (int)row=2; (int)column = 3, will produce a concatenated 2D array {{1,2,1,2,1,2}{3,4,3,4,3,4}}.
My attempt was to use a nested for loop to expand them both horizontally and and vertically, but was unsuccessful. This is what I have so far:
int row = 2;
int column = 5;
int count = 0;
int[][] list = {{12,3},{3,4}};
int [][] renewed = new int[row*list.length][column*list[0].length];
for (int l = 0; l<list.length; l++) {
for (int k = 0; k<renewed.length; k+= list.length) {
renewed[l+k] = list[l];
}
}
System.out.println(Arrays.deepToString(renewed));
}
}
^This produces list[][] expanded vertically, for the first column
int row = 2;
int column = 4;
int[][] list = {{12,3},{3,4}};
int [][] renewed = new int[row*list.length][column*list[0].length];
for (int i = 0; i<list[0].length; i++) {
for (int j = 0; j<renewed[0].length; j+=list[0].length) {
renewed[0][j+i] = list[0][i];
}
}
System.out.println(Arrays.toString(renewed[0]));
}
^This produces list[][] expanded horizontally, for the first row;
So how can I concatenate these two methods in order to produce a method that expands BOTH horizontally and vertically?
Upvotes: 1
Views: 586
Reputation: 37655
I think the easiest way is to iterate over every position in the new array and use the remainder operator %
to get the right entry of the original.
int[][] list = {{1,2},{3,4}};
int row = 2;
int column = 5;
int [][] renewed = new int[row*list.length][column*list[0].length];
for (int i = 0; i < renewed.length; i++) {
for (int j = 0; j < renewed[0].length; j++) {
renewed[i][j] = list[i % list.length][j % list[0].length];
}
}
System.out.println(Arrays.deepToString(renewed));
Upvotes: 2