CODEWITHSUNDEEP
java
Jhon House
Jhon House

Reputation: 1

How to extract a integer from a binary string and save it in a matrix?

I have a properties file that contains this information:

info.row1=1100011
info.row2=1000001
info.row3=0001000
info.row4=0011100
info.row5=0001000
info.row6=1000001
info.row7=1100011

Also I have a matrix like this 

info = new int[7][7];

I want to save each int number in a part of the matrix, like this:

    ---------------
    |1|1|0|0|0|1|1|
    ---------------
    |1|0|0|0|0|0|1|
    ---------------
    |0|0|0|1|0|0|0|
    ---------------
    |0|0|1|1|1|0|0|
    ---------------
    |0|0|0|1|0|0|0|
    ---------------
    |1|0|0|0|0|0|1|
    ---------------
    |1|1|0|0|0|1|1|
    ---------------

How can I do that? I have this code that works well until now, I just need to save that info in the matrix.

 private void startInfo(Properties data)
    {
        info = new int[7][7];

        for(int i = 0; i < 7; i++)
        {
            for(int j = 0; j < 7; j++)
            {
                String estate = data.getProperty( "info.row" +i );
                info[i][j] = ???????????;
            }
        }
    }

Upvotes: 0

Views: 105

Answers (4)

Jhon House
Jhon House

Reputation: 1

Thanks to all for the answer, you all resolved my doubt. Although, what no one realized (including me) is that my properties data started in 1, for example the first line was "info.row1", so when we started the first "for" in 0, we were searching for something that didnt exist, and a nullpointerexception error was caused. So the solution is to add 1 to i and problem solved. THANKS

Upvotes: 0

Yassin Hajaj
Yassin Hajaj

Reputation: 21995

Here is a solution using RegExs and a loop

Matcher m = Pattern.compile("=\\d*").matcher("info.row1=1100011 info.row2=1000001 info.row3=0001000 info.row4=0011100 info.row5=0001000 info.row6=1000001 <info.row7=1100011");
int[][] info = new int[7][7];
int counter = 0;

while (m.find()){
    String s = m.group(0).substring(1);
    for (int i = 0 ; i < s.length() ; i++){
        info[counter][i] = s.charAt(i);
    }
    counter++;
}

Upvotes: 0

Elliott Frisch
Elliott Frisch

Reputation: 201497

You could use Character.digit(char, int) to perform the int conversion. Something like

info = new int[7][7];
for (int i = 0; i < info.length; i++) {
  String estate = data.getProperty(String.format("info.row%d", i + 1));
  char[] line = estate.toCharArray();
  for (int j = 0; j < line.length; j++) {
    info[i][j] = Character.digit(line[j], 10);
  }
}

Upvotes: 0

Reut Sharabani
Reut Sharabani

Reputation: 31339

Read the data once per row and use the String.charAt function to map to integers:

private void startInfo(Properties data) {
    info = new int[7][7];

     for (int i = 0; i < 7; i++) {
         // only read once per row
         String estate = data.getProperty( "info.row" +i );
         for (int j = 0; j < 7; j++) {
             // map '0' to 0, anything else to '1'
             info[i][j] = estate.charAt(j) == '0' ? 0 : 1;
         }
    }
}

Upvotes: 2

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