Reputation: 211
How can I search through the entire row in a pandas dataframe for a phrase and if it exist create a new col where says it says 'Yes' and what columns in that row it found it in? I would like to be able to ignore case as well.
Upvotes: 1
Views: 192
Reputation: 5896
You could use Pandas apply
function, which allows you to traverse rows or columns and apply your own function to them.
For example, given a dataframe
+--------------------------------------+------------+---+
| deviceid | devicetype | 1 |
+--------------------------------------+------------+---+
| b569dcb7-4498-4cb4-81be-333a7f89e65f | Google | 1 |
| 04d3b752-f7a1-42ae-8e8a-9322cda4fd7f | Android | 2 |
| cf7391c5-a82f-4889-8d9e-0a423f132026 | Android | 3 |
+--------------------------------------+------------+---+
Define a function
def pr(array, value):
condition = array[array.str.contains(value).fillna(False)].index.tolist()
if condition:
ret = array.append(pd.Series({"condition":['Yes'] + condition}))
else:
ret = array.append(pd.Series({"condition":['No'] + condition}))
return ret
Use it
df.apply(pr, axis=1, args=('Google',))
+---+--------------------------------------+------------+---+-------------------+
| | deviceid | devicetype | 1 | condition |
+---+--------------------------------------+------------+---+-------------------+
| 0 | b569dcb7-4498-4cb4-81be-333a7f89e65f | Google | 1 | [Yes, devicetype] |
| 1 | 04d3b752-f7a1-42ae-8e8a-9322cda4fd7f | Android | 2 | [No] |
| 2 | cf7391c5-a82f-4889-8d9e-0a423f132026 | Android | 3 | [No] |
+---+--------------------------------------+------------+---+-------------------+
Upvotes: 1