Reputation: 153
I am trying to delay each image by one second after the other. But the delay doesn't seem to work.
$( document ).ready(function() {
$("#logo1").slideToggle(1000,"easeOutBounce");
$("#logo2").delay(1000).slideToggle(1000,"easeOutBounce");
$("#logo3").delay(2000).slideToggle(1000,"easeOutBounce");
$("#logo4").delay(3000).slideToggle(1000,"easeOutBounce");
$("#logo5").delay(4000).slideToggle(1000,"easeOutBounce");
$("#logo6").delay(5000).slideToggle(1000,"easeOutBounce");
$("#logo7").delay(6000).slideToggle(1000,"easeOutBounce");
$("#logo8").delay(7000).slideToggle(1000,"easeOutBounce");
$("#logo9").delay(8000).slideToggle(1000,"easeOutBounce");
$("#logo10").delay(9000).slideToggle(1000,"easeOutBounce");
$("#logo11").delay(10000).slideToggle(1000,"easeOutBounce");
$("#logo12").delay(11000).slideToggle(1000,"easeOutBounce");
$("#logo13").delay(12000).slideToggle(1000,"easeOutBounce");
});
And the HTML
<img src="images/logo/L.png" id="logo1" />
<img src="images/logo/Y.png" id="logo2" />
<img src="images/logo/O.png" id="logo3" />
<img src="images/logo/N.png" id="logo4" />
<img src="images/logo/S.png" id="logo5" />
<img src="images/logo/&.png" id="logo6" />
<img src="images/logo/S.png" id="logo7" />
<img src="images/logo/H.png" id="logo8" />
<img src="images/logo/A.png" id="logo9" />
<img src="images/logo/N.png" id="logo10" />
<img src="images/logo/N.png" id="logo11" />
<img src="images/logo/A.png" id="logo12" />
<img src="images/logo/N.png" id="logo13" />
The CSS positions the images one after the other.
Please could somebody take a look.
Thanks.
Upvotes: 2
Views: 401
Reputation: 153
I seemed to have solved it. I'm not sure if this is the best way but it works. (I altered the times too)
$( document ).ready(function() {
$("#logo1").slideDown(1000);
function logo2(){
$("#logo2").slideDown(1000);
}setTimeout(logo2, 300);
function logo3(){
$("#logo3").slideDown(1000);
}setTimeout(logo3, 600);
function logo4(){
$("#logo4").slideDown(1000);
}setTimeout(logo4, 900);
function logo5(){
$("#logo5").slideDown(1000);
}setTimeout(logo5, 1200);
function logo6(){
$("#logo6").slideDown(1000);
}setTimeout(logo6, 1500);
function logo7(){
$("#logo7").slideDown(1000);
}setTimeout(logo7, 1800);
function logo8(){
$("#logo8").slideDown(1000);
}setTimeout(logo8, 2100);
function logo9(){
$("#logo9").slideDown(1000);
}setTimeout(logo9, 2400);
function logo10(){
$("#logo10").slideDown(1000);
}setTimeout(logo10, 2700);
function logo11(){
$("#logo11").slideDown(1000);
}setTimeout(logo11, 3000);
function logo12(){
$("#logo12").slideDown(1000);
}setTimeout(logo12, 3300);
function logo13(){
$("#logo13").slideDown(1000);
}setTimeout(logo13, 3600);
});
Thanks for your help
Upvotes: 0
Reputation:
From doc:
The .delay() method is best for delaying between queued jQuery effects.
e.g.
$('#test').show().delay(1000).hide();
In your case, I suggest
1. Chain it
$("#logo1").slideToggle(1000,"easeOutBounce", function()
{
$("#logo2").slideToggle(1000,"easeOutBounce", function()
{
// do something after logo2 finished sliding.
// keep doing this until logo13..
});
});
2. Use deferred object
$(function(){
function slide(elem)
{
var deferred = $.Deferred();
$(elem).slideToggle(1000,"easeOutBounce", function()
{
deferred.resolve();
});
return deferred.promise();
}
var logos = ['#logo1', '#logo2', '#logo3'];
var i = 0;
function runSlider()
{
slide(logos[i]).done(function(){
i++;
if (logos[i] != null) runSlider();
});
}
});
I prefer the 2nd one though. And btw, I haven't tested this code yet. Good luck.
Upvotes: 2