Reputation: 55
I'm making a Caesar cipher and everything is exactly how I wanted it but when it comes to validation if I enter '123' it outputs 'Your translated text is: 123' when I want it to return back to getMessage() and tell the user that the input was invalid. Help would be greatly appreciated because I have been struggling with this for days.
Thanks in advance.
def getMode():
while True:
mode = input('Do you wish to encrypt(e) or decrypt(d) a message: ').lower()
if mode in 'encrypt e decrypt d'.split():
return mode
else:
print('Enter either "encrypt" or "e" or "decrypt" or "d".')
def getMessage():
message = input('Enter your message: ')
return message
def getKey():
key = 0
while True:
key = 5
return key
def getTranslatedMessage(mode, message, key):
if mode[0] == 'd':
key = -key
translated = ''
for symbol in message:
if symbol.isalpha():
num = ord(symbol)
num += key
if symbol.isupper():
if num > ord('Z'):
num -= 26
elif num < ord('A'):
num += 26
elif symbol.islower():
if num > ord('z'):
num -= 26
elif num < ord('a'):
num += 26
translated += chr(num)
else:
translated += symbol
return translated
mode = getMode()
message = getMessage()
key = getKey()
print('Your translated text is: ', getTranslatedMessage(mode, message, key))
Upvotes: 2
Views: 507
Reputation: 180481
If you just want to allow alpha characters:
def getMessage():
while True:
message = input('Enter your message: ')
if message.isalpha():
return message
print("Invalid input, text must contain alphabetic characters only.")
To allow spaces and letters:
if all(ch.isalpha() or ch.isspace() for ch in message):
return message
A dict and using modulo is going to be a much more concise approach:
def get_mode():
while True:
mode = input('Do you wish to encrypt(e) or decrypt(d) a message: ').lower()
if mode.lower() in {"e","d"}:
return mode
print('Enter either "encrypt" or "e" or "decrypt" or "d".')
def get_message():
while True:
message = input('Enter your message: ')
if all(ch.isalpha() or ch.isspace() for ch in message):
return message
print("Invalid input, text must contain alphabetic characters only.")
def get_key():
return 5
from string import ascii_letters
d = {k: i for i, k in enumerate(ascii_letters)}
enc = ascii_letters
def get_translated_message(mode, message, key):
if mode == "e":
return "".join([enc[(d[ch] + key) % 52] if not ch.isspace() else ch for ch in message])
return "".join([enc[(d[ch] - key) % 52] if not ch.isspace() else ch for ch in message])
Just run it the same way:
mode = get_mode()
message = get_message()
key = get_key()
print('Your translated text is: ', get_translated_message(mode, message, key))
Upvotes: 3
Reputation: 26590
You mentioned you want to return an error if the user enters something like '123'. Based off of that requirement, the problem in your code is right here:
You are doing this check:
if symbol.isalpha():
Which will check if something is of alpha: A-Z
Therefore, in your else, you want to return your error when the alpha check fails:
So when you do this:
else:
translated += symbol
You want this:
else:
return "input invalid"
However, again, focusing on your code, this brings up another problem. You need to change how you are handling the return of your method, so the output makes more sense. You might want to consider something like this:
mode = getMode()
message = getMessage()
key = getKey()
result = getTranslatedMessage(mode, message, key)
if not result:
print("invalid")
else:
print('Your translated text is: ', result)
Based on recent updates, you are looking to preserve whitespace. Therefore, you should consider changing your code to also handle whitespace by simply adding an elif
condition for checking for whitespace and adding ' '
to your translated
variable. So, the code in your for loop would then look like this:
for symbol in message:
if symbol.isalpha():
num = ord(symbol)
num += key
if symbol.isupper():
if num > ord('Z'):
num -= 26
elif num < ord('A'):
num += 26
elif symbol.islower():
if num > ord('z'):
num -= 26
elif num < ord('a'):
num += 26
translated += chr(num)
elif symbol.isspace():
translated += ' '
else:
return False
But Padraic's approach is really good and is definitely worth a look to consider refactoring.
Upvotes: 2