Reputation: 1455
I can't use gulp-browserify. My input file is _/components/js/script.js (this has require('jquery'). I want it to output to _/js/script.js. What's wrong with my configuration? I get a path error.
var gulp = require('gulp'),
sass = require('gulp-sass'),
uglify = require('gulp-uglify'),
browserify= require('browserify');
gulp.task('watch', function(){
gulp.watch('_/components/sass/*.scss', ['sass']);
});
gulp.task('browserify', function(){
var b = browserify({entries: './_/components/js/script.js', debug: true});
return b.bundle()
.pipe(gulp.dest('./js/'));
});
gulp.task('default', ['sass', 'browserify', 'watch']);
Upvotes: 0
Views: 120
Reputation: 14423
You can't pipe browserify
bundle stream like that to a gulp.dest
stream. It's expecting a vinyl stream. You could use vinyl-source-stream
to transform it. This is very common:
var gulp = require('gulp'),
browserify = require('browserify'),
source = require('vinyl-source-stream');
var files = ['./js/admin.js', './js/login.js', './js/main.js']
gulp.task('browserify', function(){
var b = browserify(files);
b.bundle()
.pipe(source('bundle.js'))
.pipe(gulp.dest('public'))
});
Upvotes: 1