Reputation: 18719
I am wondering how can I rewrite the following factory into a TypeScript code. Here is the original code:
app.factory('errorInterceptor', function ($q) {
return {
responseError: function (response) {
console.error("Error: " + response.statusText);
return $q.reject(response);
}
}
});
So far I've tried the following:
export class errorInterceptor {
constructor(private $q:ng.IQService) {
}
public responseError(response:any){
console.error("Error: " + response.statusText);
return this.$q.reject(response);
}
public static getFactory(){
return errorInterceptor;
}
}
app.factory('errorInterceptor',errorInterceptor.getFactory());
But I get the following error:
Provider 'errorInterceptor' must return a value from $get factory method.
Any ideas?
Upvotes: 6
Views: 295
Reputation: 7
Use this core: https://github.com/aleksey-pastuhov/AngularJS-Typed-Core/blob/master/AngularJSTypedCore/Script/service.ts
@service(app)
export class UserRolesService {
static $inject: string[] = ["$cookies"];
private $cookies: angular.cookies.ICookiesService;
user: IUser;
GetUser(): IUser {
return this.user;
}
}
Call:
this.userRolesService.GetUser()
Upvotes: -1
Reputation: 123881
I use this syntax:
export class errorInterceptor {
// to support minification
static $inject = ["$q"];
constructor(private $q:ng.IQService) {
}
public responseError(response:any){
console.error("Error: " + response.statusText);
return this.$q.reject(response);
}
//public static getFactory(){
// return errorInterceptor;
//}
}
//app.factory('errorInterceptor',errorInterceptor.getFactory());
app.service('errorInterceptor',errorInterceptor);
EXTEND:
This is the snippet which I use to intercept $http
calls (so it does work for me)
module MyModule
{
var app = angular.module("MyModule");
export class HttpErrorAspect
{
static $inject = ["$q"];
constructor(private $q: ng.IQService)
{
}
public responseError = (rejection: any): any =>
{
// do some magic, e.g. use toaster or alerter
// to notify about the issue
...
// reject that all
return this.$q.reject(rejection);
}
}
app.service("HttpErrorFilter", MyModule.HttpErrorAspect);
}
Upvotes: 2